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snow_tiger [21]
3 years ago
6

The table of values represents an exponential function ​f(x). What is the average rate of change over the interval −2≤x≤2 ? Ente

r your answer, as a decimal rounded to the nearest hundredth, in the box. x f(x) −3 8 −2 4 −1 2 0 1 1 12 2 14 3
Mathematics
1 answer:
solong [7]3 years ago
8 0

Answer:

2.50

Step-by-step explanation:

The average rate of change over the interval −2≤x≤2 is:

(f(2) − f(-2)) / (2 − -2)

From the table, we see that f(2) = 14 and f(-2) = 4.

(14 − 4) / (2 − -2)

10 / 4

2.50

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Answer:

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Step-by-step explanation:

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The measure of an angle is 28 degrees less than its supplement. find the supplement
barxatty [35]

Supplementary angles measure 180°. Make an equation:

x+(x+28) = 180

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Your new equation is:

2x=152

Divide both sides by 2 to leave the variable alone

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4 years ago
The class average on a math test was an 82 with a standard deviation of 5. If the 
Alex787 [66]

Answer:

Option 3 and 4.

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 82, standard deviation (σ) = 5

1) For x = 74:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{74-82}{5} =-1.6

Option 1 is incorrect

2) For x < 87

z=\frac{x-\mu}{\sigma} \\\\z=\frac{87-82}{5} =1

From the normal distribution table, P(x < 87) = P(z < 1) = 0.8413 = 84.13%

Option 2 is incorrect

3) For x = 95:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{95-82}{5} =2.6

Option 3 is correct

4) For x < 77

z=\frac{x-\mu}{\sigma} \\\\z=\frac{77-82}{5} =-1

From the normal distribution table, P(x < 77) = P(z < -1) = 0.16 = 16%

Option 4 is correct

5) For x > 92

z=\frac{x-\mu}{\sigma} \\\\z=\frac{92-82}{5} =2

From the normal distribution table, P(x > 92) = P(z > 2) = 1 - P(z < -2) = 1 - 0.9772 = 0.0228 = 2.28%

Option 5 is incorrect

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3 years ago
Plss help
KonstantinChe [14]

\frac{1}{2} \times 5 \times 16 \\ 40 \\ ke = 40joules

if correct mark me as brainiest

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3 years ago
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