The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
More about the work done for isothermal process link is given below.
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Answer is 20 by plugging the 4 in the equation it equals 20
What number comes after 12 24 72 to 288 first please explain that again and second 11 comes after 12 and 23 comes after 24 and 71 comes after 72 hope this helps
Answer:x = 75
Step-by-step explanation:y=105 - 5 = 100 ft
z=125 ft
dz/dt=2 ft/sec
by using Pythagorean Theorem, we find x
x^2 + 100^2 = 125^2
x = 75
