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4 years ago

What is the prime factorization of 147?

Mathematics

2 answers:

Mice21 [21]4 years ago

8 0

Answer:

B. 3×7×7

Step-by-step explanation:

147

49 * 3

7 * 7 * 3

matrenka [14]4 years ago

3 0

I also believe the answer is B

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Evaluate.<br> pls I need

Kaylis [27]

Hi! The answer is 231.25.
The answer is 231.25 because 8,325 / 36 is 231.25 I hope this helped! Goodluck :)

4 0

4 years ago

Pls help i really need it

olchik [2.2K]

Answer:

I think if you look up the equation on google there is a calculator and you may get some of your answers there

Step-by-step explanation:

8 0

3 years ago

The price elasticity of demand for good X is half the price elasticity of Good Y. A 20% rise in the price of good X results in a

Keith_Richards [23]

The answer is

60% rise in quantity demanded of good x.

Explanation:

Percentage change in quantity demanded for good Y:

= (Change in Quantity ÷ Initial Quantity) × 100

= (60 units ÷ 400 units) × 100

= 15%

Percentage change in price of good Y = 10% Rise

Therefore, the price elasticity of demand for Good Y is as follows:

= Percentage change in Quantity demanded ÷ Percentage change in price

= 15 ÷ 10

= 1.5

Hence,

Price elasticity of demand of good x:

= 2 × price elasticity of demand of good y

= 2 × 1.5

= 3

Percentage change in price of good x:

= (Change in price ÷ Initial price) × 100

= (2 ÷ 10) × 100

= 20%

Therefore,

Price elasticity of demand for Good x = Percentage change in Quantity demanded ÷ Percentage change in price

3 = Percentage change in Quantity demanded ÷ 20

3 × 20 = Percentage change in Quantity demanded

60% = Percentage change in Quantity demanded for good x

Hence, 60% rise in quantity demanded of good x.

7 0

3 years ago

Find the value of the variable and DF if D is between C and F if CD 4y -9, DF 2y-7, and CF 14.

Yuri [45]

CF = CD + DF (since D is simply a point on the line, and C to that point added onto F to that point is CF), so 4y-9+2y-7=14. Adding it up, we get 6y-16=14 and adding by 16 we get 30=6y. Dividing both sides by 6, we get y=5. Plugging that into DF, we get 10-7=DF=3

4 0

3 years ago

Two points are separated on the ground by a distance of 43 km. Can they be placed on a 1 / 25000th map with dimensions 1.32 m on

Wittaler [7]

Answer:

Explanation:

The distance between the two points on the ground = 43km

$\text{Scale}=\frac{1}{25000}$

First, we calculate the distance between the two points in meters.

• 43km = 43,000 m.

Next, determine the distance it will take using the scale.

$\begin{gathered} \frac{1}{25000}=\frac{x}{43000} \\ 25000x=43000 \\ x=\frac{43000}{25000} \\ x=1.72m \end{gathered}$

The distance between the points using the scale is 1.72m.

Next, we see that the dimensions (1.32 m by 0.85 m) are smaller than the length.

As a final check, calculate the length of the diagonal of the map. The diagonal is usually the longest part.

$\text{Diagonal}=\sqrt[]{1.32^2+0.85^2}=1.57m$

Since 1.57m is still less than 1.72m, the two points cannot be placed on the map.

7 0

1 year ago