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Artyom0805 [142]
4 years ago
15

Which expression is a perfect cube?

Mathematics
2 answers:
Bingel [31]4 years ago
7 0

we know that

A perfect cube is a whole number which is the cube of another whole number or a number is a perfect cube if the cube root of that number is a whole number.

so

<u>case a)</u> 12x^{12} y^{18}

12x^{12} y^{18} = 12(x^{4} y^{6})^{3}

the cube root of 12 is not a whole number

therefore

<em><u>The expression is not a perfect cube</u></em>

<u>case b)</u> 12x^{27} y^{125}

12x^{27} y^{125} = 12(x^{9})^{3}y^{125}

the cube root of 12 is not a whole number

the cube root of y^{125} is not a whole number

therefore

<em><u>The expression is not a perfect cube</u></em>

<u>case c)</u> 64x^{15} y^{18}

64x^{15} y^{18} = (4 x^{5} y^{6})^{3}

therefore

<em><u>The expression is a perfect cube</u></em>

<u>case d)</u> 64x^{27} y^{125}

64x^{27} y^{125} = (4 x^{9})^{3}y^{125}

the cube root of y^{125} is not a whole number

therefore

<em><u>The expression is not a perfect cube</u></em>

<u>the answer is</u>

64x^{15} y^{18}

DIA [1.3K]4 years ago
6 0
The expression that is a perfect cube is D. Because to determine the side length of a cube we would need to take the cube root of the number and the variables and unlike the other answers we can't take the cube root out perfectly. For D though the side length is calculated by taking the cube root of 64, which is 4, cube root of x^27 which is x^3, and cube root of y^125 which is y^5. Putting everything together the side length should be 4X^3Y^5. Multiplying this expression by itself 3 times will give you what you started out with.
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