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4 years ago

Need help doing this

Mathematics

1 answer:

Nat2105 [25]4 years ago

3 0

hmmm..oh ok thats easy/ first try solving it urself and then really think about it. if ya dont get the answer friend me and i will give u the answer

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14:56 in it simplest form

romanna [79]

They both can be divided by 2 to make it 7: 28. Then, it can be divided by 7 to make it 1:4

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3 years ago

Mayra bought $$ grams of rice. Anika bought $$ more than Mayra bought. Select ALL of the equations that represent the relationsh

Sonja [21]

Answer:

Step-by-step explanation:2

4 0

3 years ago

56% of all violent felons in the prison system are repeat offenders. If 31 violent felons are randomly selected, find the probab

SashulF [63]

Answer:

a) 0.1261

b) 0.3756

c) 0.4828

d) 0.8329

Step-by-step explanation:

The given scenario indicates the probability distribution with n=31 and p=0.56.

The pdf of binomial distribution is

P(X=x)=nCx(p^x)(q^n-x).

n=31, p=0.56 and q=1-p=1-0.56=0.44.

All the probabilities rounded off to four decimal places.

a. P(Exactly 16 of them are repeat offenders)=P(X=16)

P(X=16)=31C16(0.56)^16(0.44)^15

P(X=16)=300540195(0.00009354)(0.0000044850)

P(X=16)=0.1261

b. P(At most 16 of them are repeat offenders)=P(X≤16)

P(X≤16)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)+P(X=11)+P(X=12)+P(X=13)+P(X=14)+P(X=15)+P(X=16)

P(X=0)=31C0*(0.56)^0*(0.44)^31=0.0000

P(X=1)=31C1*(0.56)^1*(0.44)^30=0.0000

P(X=2)=31C2*(0.56)^2*(0.44)^29=0.0000

P(X=3)=31C3*(0.56)^3*(0.44)^28=0.0000

P(X=4)=31C4*(0.56)^4*(0.44)^27=0.0000

P(X=5)=31C5*(0.56)^5*(0.44)^26=0.0000

P(X=6)=31C6*(0.56)^6*(0.44)^25=0.0000

P(X=7)=31C7*(0.56)^7*(0.44)^24=0.0001

P(X=8)=31C8*(0.56)^8*(0.44)^23=0.0005

P(X=9)=31C9*(0.56)^9*(0.44)^22=0.0016

P(X=10)=31C10*(0.56)^10*(0.44)^21=0.0044

P(X=11)=31C11*(0.56)^11*(0.44)^20=0.0106

P(X=12)=31C12*(0.56)^12*(0.44)^19=0.0226

P(X=13)=31C13*(0.56)^13*(0.44)^18=0.0420

P(X=14)=31C14*(0.56)^14*(0.44)^17=0.0687

P(X=15)=31C15*(0.56)^15*(0.44)^16=0.0991

P(X=16)=31C16*(0.56)^16*(0.44)^15=0.1261

So,

P(X≤16)=0.0000+0.0000+0.0000+0.0000+0.0000+0.0000+0.0000+0.0001+0.0005+0.0016+0.0044+0.0106+0.0226+0.042+0.0687+0.0991+0.1261

P(X≤16)=0.3756

c. P(At least 18 of them are repeat offenders)=P(X≥18)

P(X≥18)=1-P(X<18)=1-P(X≤17)

P(X≤17)=P(X≤16)+P(X=17)

P(X=17)=31C17*(0.56)^17*(0.44)^14=0.1416

P(X≤17)=0.3756+0.1416=0.5172

P(X≥18)=1-0.5172

P(X≥18)=0.4828

d. P(Between 13 and 20 (including 13 and 20) of them are repeat offenders) =P(13≤X≤20)

P(13≤X≤20)=P(X=13)+P(X=14)+P(X=15)+P(X=16)+P(X=17)+P(X=18)+P(X=19)+P(X=20)

We have already find the P(X=13),P(X=14),P(X=15), P(X=16) and P(X=17) in above calculations. We only have to find P(X=18), P(X=19) and P(X=20).

P(X=18)=31C18*(0.56)^18*(0.44)^13=0.1402

P(X=19)=31C19*(0.56)^19*(0.44)^12=0.1221

P(X=20)=31C20*(0.56)^20*(0.44)^11=0.0932

P(13≤X≤20)=0.042+0.0687+0.0991+0.1261+0.1416+0.1402+0.1221+0.0932

P(13≤X≤20)=0.8329

4 0

3 years ago

PLEASE HELP

Law Incorporation [45]

I'd personally go with A and C, The rest don't make too much sense. Don't count on my answer just yet though.

7 0

3 years ago

Solve for X showing every step

Rashid [163]

Answer:

x = 1

Step-by-step explanation:

3(x + 6) -5 = 16

You want to first add the 5 (*flipping the sign) over to the 16

making your equation ...

3(x +6) = 21

Then you want to distribute the 3 to x and 6

making you equation

3x + 18 = 21

Then you want to subtract the 18 (*flipping the sign) to the right side

making the equation....

3x = 3

Lastly, divide the 3 on the left to the 3 on the right making the answer 1

x = 1

8 0

3 years ago