2x^2-13x+20=2x <br> 2<br> −13x+20

*EXTRA PTS* how much salsa is missing from the jar

Anna71 [15]

I could be wrong but I think it’s the first one

Hope I helped

3 0

3 years ago

The ages of a random sample of five university professors are 39, 54, 61, 72, and 59. Using this information, find a 99% confide

kondor19780726 [428]

Answer:

99% confidence interval for the population standard deviation = (74.97 , 635.20).

Step-by-step explanation:

We are given that the ages of a random sample of five university professors are 39, 54, 61, 72 and 59. Also, it is provided that the ages of university professors are normally distributed.

So, firstly the pivotal quantity for 99% confidence interval for the population standard deviation is given by;

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

where, s = sample standard deviation

$\sigma$ = population standard deviation

n = sample of university professors = 5

Also, $s^{2}$ = $\frac{\sum (X-\bar X)^{2} }{n-1}$ = 144.5

So, 99% confidence interval for population standard deviation, $\sigma$ is;

P(0.2070 < $\chi^{2} __5_-_1$ < 14.86) = 0.99 {As the table of $\chi^{2}$ at 4 degree of freedom

gives critical values of 0.2070 & 14.86}

P(0.2070 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 14.86) = 0.99

P( $\frac{ 0.2070}{(n-1)s^{2} }$ < $\frac{1 }{\sigma^{2} }$ < $\frac{ 14.86}{(n-1)s^{2} }$ ) = 0.99

P( $\frac{ (n-1)s^{2}}{14.86 }$ < $\sigma^{2}$ < $\frac{ (n-1)s^{2}}{0.2070 }$ ) = 0.99

99% confidence interval for $\sigma^{2}$ = ( $\frac{ (n-1)s^{2}}{14.86 }$ , $\frac{ (n-1)s^{2}}{0.2070 }$ )

= ( $\frac{ (5-1) \times 144.5^{2}}{14.86 }$ , $\frac{ (5-1) \times 144.5^{2}}{0.2070 }$ )

= (5620.525 , 403483.092)

99% confidence interval for $\sigma$ = ( $\sqrt{5620.525}$ , $\sqrt{403483.092}$ )

= (74.97 , 635.20)

Therefore, 99% confidence interval for the population standard deviation of the ages of all professors at the university is (74.97 , 635.20).

8 0

4 years ago

Bella earned $216 in interest after 4 years on a principal of $1,500. What is her interest rate?

katrin2010 [14]

Answer:

R = 148.6111%/year

Equation:

r = (1/t)(A/P - 1)

Calculation:

Solving our equation:

r = (1/4)((1500/216) - 1) = 1.48611111

r = 1.48611111

Converting r decimal to R a percentage

R = 1.48611111 * 100 = 148.6111%/year

The interest rate required to get a total amount, principal plus interest, of $1,500.00 from simple interest on a principal of $216.00 over 4 years is 148.6111% per year.

4 0

3 years ago

Read 2 more answers

BRAINLIEST TO CORRECT ANSWER

STatiana [176]

The area of the given figure is 38 square units

<h3>Area of a trapezoid</h3>

The area of the given trapezoid is expressed as:

A = 0.5(a+b)h

where

a and b are the sides

h is the height

Substitute

A = 0.5(9+10) * 4

A = 19 * 2

A = 38 square units

Hence the area of the given figure is 38 square units

Learn more on area of trapezoid here: brainly.com/question/1463152

#SPJ1

7 0

2 years ago

Write the ratio in simplest form 60/45

Bond [772]

Answer: BRAINLIEST PLZ

4/3

Step-by-step explanation:

60/45 => both divisible by 15

60÷15=4

45÷15=3

4/3 is the answer!!

BRAINLIEST PLZ

8 0

3 years ago

Read 2 more answers

2x^2-13x+20=2x 2 −13x+20