All categories

3 years ago

Find (7 × 105) + (2 × 103).

Mathematics

2 answers:

alina1380 [7]3 years ago

7 0

7x105=735
2×103=206
735+206=941 is that answer

Alisiya [41]3 years ago

6 0

7 × 105 = 735
2 × 103 = 206
735 + 206 = 941

Your answer is 941.

Hope this helps!

You might be interested in

Graph the function f(x)=(x+1)(x-2)

creativ13 [48]

F(x) = (x + 1)(x - 2)
f(x) = x(x - 2) + 1(x - 2)
f(x) = x(x) - x(2) + 1(x) - 1(2)
f(x) = x² - 2x + x - 2
f(x) = x² - x - 2

6 0

3 years ago

Write An expression of the fourth degree with a leading coefficient of 5, a quadratic term with a coefficient of 3, a linear ter

Svetllana [295]

Answer:

${5x}^{4} + 3 {x}^{2} - 8x + 6$

Step-by-step explanation:

Math

5 0

2 years ago

Which two prime numbers' product is 226

saw5 [17]

Answer:

<h2>Solution: Since, the prime factors of 226 are 2, 113. Therefore, the product of prime factors = 2 × 113 = 226.</h2>

Step-by-step explanation:

<h2>(｡♡‿♡｡)______________________</h2><h2>PLEASE MARK ME BRAINLIEST AND FOLLOW M E AND SOUL DARLING TEJASWINI SINHA HERE ❤️</h2>

4 0

3 years ago

Read 2 more answers

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago

If 9 out of 10 doctors in a small city recommend afternoon naps, and there are 8 doctors in the city who don’t recommend naps, h

Hitman42 [59]

Answer:

Step-by-step explanation:

1 out of 10 do not recommend naps, so 9 times as many do recommend naps.

9 × (8 doctors) = 72 doctors . . . . . recommend naps

3 0

2 years ago