I think that it is B because I'm pretty sure it has to be log of 50,000. But I forgot how to get the rest of it but B is the only one with log of 50k.
Answer:
6/5
Step-by-step explanation:
2/5*3=2/5*3/1=6/5
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
Answer:
x =
of y
Step-by-step explanation:
Given:
15% of x equals 20% of y
So,
0.15x = 0.20y
so
x = 0.20 y / 0.15
x = 1.3333y
x =
of y
Answer:
Step-by-step explanation:
![\frac{8}{32} = \frac{4}{16} = \frac{2}{8} = \frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B32%7D%20%20%3D%20%20%5Cfrac%7B4%7D%7B16%7D%20%20%3D%20%20%5Cfrac%7B2%7D%7B8%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B4%7D%20)
![\frac{27}{54} = \frac{9 }{18} = \frac{3}{6} = \frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B27%7D%7B54%7D%20%20%3D%20%20%5Cfrac%7B9%20%7D%7B18%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7B6%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)
![\frac{36}{24} = \frac{18}{12} = \frac{9}{6} = \frac{3}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B36%7D%7B24%7D%20%20%3D%20%20%5Cfrac%7B18%7D%7B12%7D%20%20%3D%20%20%5Cfrac%7B9%7D%7B6%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7B2%7D%20)
![\frac{30}{60} = \frac{15}{30} = \frac{5}{10} = \frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B30%7D%7B60%7D%20%20%3D%20%20%5Cfrac%7B15%7D%7B30%7D%20%20%3D%20%20%5Cfrac%7B5%7D%7B10%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)