Answer:
The answer to this question can be given as:
Statement:
number = int(line.strip())
Explanation:
In the above statement, we declare an integer variable number accept the integer value from the file that name is line. In this line, we use the strip() function. This function returns a duplicate string with both starting and tracking characters removed (based on the string parameter passed). The strip() function removes characters from both sides (left and right) based on the parameter(a string defining the collection of characters to be removed).
Answer/Explanation:
In this scenario, you can:
- look at the existing CloudWatch logs for keywords related to the application error to create a custom metric;
- create a CloudWatch alarm for that custom metric which invokes an action to restart the EC2 instance;
- create alarms that automatically stop, terminate, reboot, or recover your EC2 instances using Amazon CloudWatch alarm actions;
- use the stop or terminate actions to help you save money when you no longer need an instance to be running; and
- use the reboot and recover actions to automatically reboot those instances or recover them onto new hardware if a system impairment occurs.
Cheers
Answer:
The solution code is written in Java.
- public class Main {
- public static void main(String[] args) {
- System.out.print("Please enter a number: ");
- Scanner console = new Scanner(System.in);
- int n = console.nextInt();
- calculateSum1(n);
- calculateSum2(n);
- calculateSum3(n);
- calculateSum4(n);
- }
- public static void calculateSum1 (int num){
- int sum1 = 0;
- for(int i=1; i <= num; i++){
- sum1 += i*i*i;
- }
- System.out.println("Sum 1 : " + sum1);
- }
- public static void calculateSum2 (int num){
- int sum2 = num * num * (num + 1) * (num + 1) / 4;
- System.out.println("Sum 2 : " + sum2);
- }
- public static void calculateSum3 (int num){
- int sum3 = 0;
- for(int i=1; i <=num; i++){
- sum3 += i;
- }
- sum3 = sum3 * sum3;
- System.out.println("Sum 3 : " + sum3);
- }
- public static void calculateSum4 (int num){
- int sum4 = (num * (num + 1) * (2*num + 1)) / (4+2);
- System.out.println("Sum 4 : " + sum4);
- }
- }
Explanation:
Firstly we create four different methods that calculate the sum of the first n cubes in different ways (Line 13 - 43).
This is important to understand the concept of operator precedence to work out the different ways of summation.
For example, The operator * and / will always have higher precedence than +.
On another hand, any expression enclosed within the parenthesis will have highest precedence and therefore the value will be evaluated prior to others.
This is also important to understand the expression evaluation will always start from left to right.
