<h3>
Answer: y = x+1</h3>
===================================================
Explanation:
f(x) = x^3 - 2x + 3
f ' (x) = 3x^2 - 2 ..... apply the power rule
f ' (1) = 3(1)^2 - 2 ... plug in x coordinate of given point
f ' (1) = 1
If x = 1 is plugged into the derivative function, then we get the output 1. This means the slope of the tangent line at (1,2) is m = 1. It's just a coincidence that the x input value is the same as the slope m value.
Now apply point slope form to find the equation of the tangent line
y - y1 = m(x - x1)
y - 2 = 1(x - 1)
y - 2 = x - 1
y = x - 1 + 2
y = x + 1 is the equation of the tangent line.
The graph is shown below. I used GeoGebra to make the graph.
Answer:
x = - 6
Step-by-step explanation:
A line with a slope of zero is a horizontal line parallel to the x- axis with equation
x = c ( where c is the value of the x- coordinates the line passes through )
The line passes through (- 6, - 7 ) with x- coordinate - 6 , then
x = - 6 ← equation of line
Answer:
It is TRUE for all Real numbers, i.e. [x] = ]x+1[ for all x∈R.
Step-by-step explanation:
Let's write given statement as [ x ] = ] x+1 [
where [ x ] step function means next integer greater than or equal to x,
and ] y [ means last integer less than or equal to y.
Let's take an example of x = 2.5
So [ 2.5 ] = 3.
and ] 2.5 + 1 [ = ] 3.5 [ = 3.
Similarly, we can take any example of Real numbers like 3.7, 4.2, 5.6, 8.9 etc.
It is TRUE for all Real numbers, i.e. [x] = ]x+1[ for all x∈R.
