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3 years ago

36 is 12%of what number

1 answer:

6 0

Let, the number = x
It would be: x * 12% = 36
x * 0.12 = 36
x = 36/0.12
x = 300

In short, Your Answer would be 300

Hope this helps!

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Herald's Printing needs to ship 56,000 programs to the Queen basket team. The printing company can fit 800 programs in each box.

sasho [114]

Answer:70

Step-by-step explanation: It’s simply division. 56,000 programs, divided into boxes, with 800 in each box, will need 70 boxes.

5 0

2 years ago

PLEASE HELP! THiS IS DUE!!!!!!!! I Will MAKE BRAINlST

9966 [12]

Answer:

$\mathrm{26.\qua\:H\quad\:2 \dfrac{ 1 }{ 4 }\qua\:mi}$

$\mathrm{27.\qua\:D\quad\: 9\dfrac{ 1 }{ 8 }\qua\:lb}$

$\mathrm{28.\qua\:H\quad\:14.6}$

$\mathrm{29.\qua\:C\quad\:25\%}$

$\mathrm{30.\qua\:J\quad\:33.912\qua\ ft^{3} }$

Step-by-step explanation:

26.

$\mathrm{\dfrac{ 3 }{ 4 }\:mile\:per\:one\:hour}$

$\mathrm{To\:find\:how\:far\:Jet's\:cousin\:can\:walk\:in\:3\:hours\:,\:we\:multiply\:\dfrac{ 3 }{ 4 }\:by\:3}$

$3 \times \dfrac{ 3 }{ 4 }$

$\mathrm{Express\: 3 \times \left( \dfrac{ 3 }{ 4 } \right)\:as\:a\:singe\:fraction}$

$\dfrac{ 3 \times 3 }{ 4 }$

$\mathrm{Multiply\:3\:and\:3\:to\:get\:9}$

$\dfrac{ 9 }{ 4 }$

$\mathrm{Convert\:\dfrac{ 9 }{ 4 }\:to\:a\:mixed\:number}$

$2 \dfrac{ 1 }{ 4 }$

$\mathrm{So\:she\:can\:walk\:2 \dfrac{ 1 }{ 4 }\:miles\:in\:3\:hours}$

27.

$\mathrm{Since\:we\:want\:to\:find\:how\:many\:pounds\:both\:pumpkins\:weigh\:together,\:we\:have\:to\:add.}$

$5 \dfrac{ 3 }{ 4 } +3 \dfrac{ 3 }{ 8 }$

$\mathrm{Turn\:both\:mixed\:fractions\:into\:improper\:fractions}$

$\dfrac{ 23 }{ 4 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Least\:common\:multiple\:of\:4\:and\:8\:is\:8}$

$\mathrm{Multiples\:of\:4}:\quad4,8,12,16,20$

$\mathrm{Multiples\:of\:8}:\quad8,16,24,32,40$

$\dfrac{ 23 }{ 4 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Convert\: \dfrac{ 23 }{ 4 } \:and\: \dfrac{ 27 }{ 8 } \:to\:fractions\:with\:denominator\:8}$

$\dfrac{ 23 \times 2 }{ 4 \times 2 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Simplify}$

$\dfrac{ 46 }{ 8 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Since\: \dfrac{ 46 }{ 8 }\:and\:\dfrac{ 27 }{ 8 }\:have\:the\:same\:denominators,\:add\:them\:by\:adding\:their\:numerators}$

$\dfrac{ 46+27 }{ 8 }$

$\mathrm{Add\:46\:and\:27\:to\:get\:73}$

$\dfrac{ 73 }{ 8 }$

$\mathrm{Convert\:\dfrac{ 73 }{ 8 }\:to\:a\:mixed\:number}$

$9 \dfrac{ 1 }{ 8 }$

$\mathrm{Both\:pumpkins\:weighed\:9 \dfrac{ 1 }{ 8 }\:pounds\:all\:together}$

28.

Since the question is asking us "How many more miles did Alyce travel than Jason", we have to subtract the miles Jason traveled from the miles Alyce traveled.

$29.193-14.593$

$\mathrm{Subtract\:14.593\:from\:29.193\:to\:get\:14.6}$

$14.6$

$\mathrm{Alyce\:traveled\:14.6\:more\:miles\:than\:Jason}$

29.

For this question, we must find "10 is what percent of 40"

The equation for this is:

$\dfrac{ 10 }{ 40 } \times 100$

$\mathrm{Simplify\: \dfrac{ 10 }{ 40 } \:to\: \dfrac{ 1 }{ 4 } }$

$\dfrac{ 1 }{ 4 } \times 100$

$\mathrm{Multiply\: \dfrac{ 1 }{ 4 }\:and\:100\:to\:get\: \dfrac{ 100 }{ 4 } }$

$\dfrac{ 100 }{ 4 }$

$\mathrm{Divide\:100\:by\:4\:to\:get\:25}$

$25$

$\mathrm{So\:she\:recieved\:a\:25\%\:off\:discount}$

To check if this is correct, you can do the following below:

What is 25 percent (%) off $40?

Use the formula and replace the given values:

Amount Saved = Original Price x Discount % / 100. So,

Amount Saved = 40 x 25 / 100

Amount Saved = 1000 / 100

Amount Saved = $10

In other words, a 25% discount for an item with original price of $40 is equal to $10

30.

Given that the calculated volume of the drum is 37.68 ft³ and it is 90% full, it implies that the current volume is calculated as:

$\mathrm{Current\:compacity} = 90 \% \times 37.68$

$\mathrm{Turn\:90\%\:into\:a\:decimal}$

$\mathrm{Current\:compacity} = 0.9 \times 37.68$

$\mathrm{Multiply\:0.9\:and\:37.68\:to\:get\:33.912}$

$33.912$

$\mathrm{The\:current\:compacity\:of\:the\:drum\:is\:33.912\:ft^{3} }$

8 0

1 year ago

Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters

Mumz [18]

The various answers to the question are:

To answer 90% of calls instantly, the organization needs four extension lines.
The average number of extension lines that will be busy is Four
For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

<h3>How many extension lines should be used if the company wants to handle 90% of the calls immediately?</h3>

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

$P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$$

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$$

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$$

Generally, the equation for is mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

The probability that a call will receive a busy signal if four extensions lines are used is,

$P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$$

Therefore, the average number of extension lines that will be busy is Four

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

$P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$$

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.