Factors and multiplesfor 8 yes or no

2 answers:

5 0

Factors 1,2,3,4 and 8
multiples are 8,16,24,32,40,48,56,64,72,80,88,96,104,112,120,128,136,144,152,160,168,176,184,1

hope this helps.

nadya68 [22]4 years ago

5 0

The factors of 8 are : 1 , 2 , 4 , 8

multiples of 8 : 8 , 16 , 24 ,32 , 40 , 48 , 56 , 64 , 72 , 80 , 88 , 96 , 104 , 112 etc..........

hope this helps you

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Translation Algebraic Expressions

SVETLANKA909090 [29]

7+k=?
4-z=?
9-x=?
c4=?
z-9=?
9+s=?
x-4=?
x-9=?
8+f=?
d/4=? or d÷4=?

4 0

3 years ago

Ms. Kuula owns a small business. In one week, she had profits of $20, $37, and $48. She also had losses of $18 and $7. What was

Llana [10]

Answer:

The answer is 80.

Step-by-step explanation:

We can get our answer using PEMDAS with the expression: (20 + 37 + 48) - ( 18 + 7) and or 105 - 25.

Do the math, and Ms. Kuula has 80 dollars for the week.

3 0

3 years ago

Plz help I have no idea how to answer it

saveliy_v [14]

5. Answer: see explanation

Step-by-step explanation:

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0 and x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0 then p = -4m and q = 3m²

3p² = 3(-4m)² 16q = 16(3m²)

= 3(16m²) = 48m²

= 48m²

3p² = 48m² = 16q ⇒ 3p² = 16q

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6. Answer: 8 or 18

Step-by-step explanation:

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

Bigger non-shaded Δ: L = 12-x, w = 10 ⇒ $A = \dfrac{10(12-x)}{2}$
Smaller non-shaded Δ: L = x, w = x ⇒ $A=\dfrac{x(x)}{2}$

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

$\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}$