To get one hour you multiply 30 by 2 so you multiply 20 by two also
this gives you 40km per hour
Can anyone help me with my questions
Hello, Your answer is below.
The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is T^2 = A^3. Let the orbital period of planet X be T(X) and that of planet Y = T(Y) and let the mean distance of planet X from the sun be A(X) and that of planet Y = A(Y), then A(Y) = 2A(X) [T(Y)]^2 = [A(Y)]^3 = [2A(X)]^3 But [T(X)]^2 = [A(X)]^3 Thus [T(Y)]^2 = 2^3[T(X)]^2 [T(Y)]^2 / [T(X)]^2 = 2^3 T(Y) / T(X) = 2^3/2 Therefore, the orbital period increased by a factor of 2^3/2.
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Your friend Papaguy.
Answer:
umm well that's would mean that all 3 triangles are the exact same bc if triangle abc is congruent to triangle xyz and triangle xyz is congruent to triangle jkl so anything that's says other size would have to be the answer