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jenyasd209 [6]
4 years ago
15

I’m so confused, please help.

Mathematics
1 answer:
grandymaker [24]4 years ago
4 0

i believe the answer is B

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A rectangular field measures 400m by 900m, what is the perimeter of the field:
Alina [70]

Answer:

a) 1790 b) 1.79

Step-by-step explanation:

a) you just add to get the perimiter 2(900) + 2(400) to get 1790

b) 1000 meters makes a kilometer so we divide by 1000 and get 1.79 for the kilometers

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3 years ago
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2x^3y + 18xy - 10x^2y - 90y Part A: Rewrite the expression so that the GCF is factored completely. (3 points)
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2y(x3+9x-10x2-45) not much to be taken as a common factor
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Given x= 5+ ✓16<br>name all possible values.<br>a.) -11<br>b.) 1<br>c.) 9<br>d.) 21
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3 years ago
A ball is thrown vertically in the air with a velocity of 90ft/s. Use the projectile formula h=−16t2+v0t to determine at what ti
Debora [2.8K]

Answer:

t=1.7 \ sec\ , t=4.0\ sec

Step-by-step explanation:

<u>Vertical Throw</u>

It refers to a situation where an object is thrown verticaly upwards with some inicial speed v_o and let in free air (no friction) until it completes its movement up and finally returns to the very same point of lauch. The only acting force is gravity

The projectile formula is given as

h=-16t^2+v_0t

where t is time in seconds, h is the height in feet and v is the speed in ft/sec

We are required to find the time t where h=120 ft, knowing v_o=90\ ft/sec

-16t^2+90t=120

Rearranging

-16t^2+90t-120=0

This is a second-degree equation which will be solved with the formula

\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\displaystyle x=\frac{-90\pm \sqrt{90^2-4(-16)(-120)}}{2(-16)}

\displaystyle x=\frac{-90\pm \sqrt{1380}}{-32}

Two solutions are obtained

\boxed{t=1.7 \ sec\ , t= 4.\ sec}

Both solutions are possible because the ball actually is at 120 ft in its way up and then when going down

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3 years ago
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Please help me please !!!
Anon25 [30]

3rd - 25 is the 3rd term in the sequence

4 0
3 years ago
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