Question

The distance d in feet that a dropped object falls in t seconds is given by the equation d divide by 16=t to the second power.How long does it take a dropped object to fall 64 feet?

Answer 1

Step-by-step explanation:

It is given that, the distance(d) that a dropped object falls in t seconds is given by the following equation as :

$\dfrac{d}{16}=t^2$............(1)

Where

d is the distance (in feet)

t is time (in seconds)

We need to find the time taken by the object to fall 64 feets. Put the value of d = 64 feet in equation (1) as :

$\dfrac{64}{16}=t^2$

$t^2=4$

t = 2 seconds

So, the object will take 2 seconds to fall 64 feets. Hence, this is the required solution.

Answer 2

Answer:16+64= 80

Step-by-step explanation: