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3 years ago

Please please help me!!

Mathematics

2 answers:

podryga [215]3 years ago

5 0

Answer: square root of three or 1.73205

Hope this helps :)

scZoUnD [109]3 years ago

3 0

Answer:

√3

Step-by-step explanation:

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Find the range of (f+g)(x) when f(x) = (x+4)^2 and g(x) = 3

qwelly [4]

$(f+g)(x)=f(x)+g(x)\\\\f(x)=(x+4)^2;\ g(x)=3\\\\(f+g)(x)=(x+4)^2+3=(x)^2+2(x)(4)+4^2+3\\\\=x^2+8x+16+3=x^2+8x+19\\\\Used:\\\\(a+b)^2=a^2+2ab+b^2$

7 0

2 years ago

Factor the expression. 2x + 8

IgorC [24]

Answer:

2x+8

2 is common

2(x+4)=0

Step-by-step explanation:

5 0

2 years ago

In the diagram, AC =BD. A.true B.false

nikdorinn [45]

Answer:

B.False

Step-by-step explanation:

Because it built different

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2 years ago

Find f(x) and g(x) so that the function can be described as y = f(g(x)). y = 4/x^2+9

dlinn [17]

I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,

One possible answer is $f(x) = \frac{4}{x}, \ \ g(x) = x^2+9$

Another possible answer is $f(x) = \frac{4}{x+9}, \ \ g(x) = x^2$

There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)

So in the first example above, we would have

$f(x) = \frac{4}{x}\\\\f( g(x) ) = \frac{4}{g(x)}\\\\f( g(x) ) = \frac{4}{x^2+9}$

In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.

Similar steps will happen with the second example as well (when g(x) = x^2)

4 0

3 years ago

the width of a rectangle is the length minus 2 units. The area of the rectangle is48 units. What is the width, in units, of the

tatuchka [14]

Answer:

Step-by-step explanation:

put unknown as y

area of rectangle = width × long

y(y - 2)=48

y² -2y =48

u can use scientific calculator to find this

y²-2y-48=0

(y-8)(y+6)=0

y=8 y=-6

take the positive value and ignore the negative value

width=y-2 long=8

8-2=6

I hope this help you :)

6 0

2 years ago