Answer:
Step-by-step explanation:
-2x + 3y – 4z = 8 ----------------(I)
5x – 3y + 5z = -8 -----------------(II)
7x – 3y + 3z = 8 ------------------(III)
Add equation (I) & (II) and thus y will be eliminated
(I) -2x + 3y – 4z = 8
(II) <u>5x – 3y + 5z = -8</u> {Add}
3x + z = 0 ------------------------(A)
Multiply equation (II) by (-1) and then add with equation (III). Thus y will be eliminated.
(II) * (-1) -5x + 3y - 5z = +8
<u>7x – 3y + 3z = 8</u> {Add}
2x -2z = 16 ---------------(B)
Multiply equation (A) by 2 and then add. Thus z will be eliminated and we will get the value of x
(A) * 2 6x + 2z = 0
(B) <u>2x - 2z = 16</u> {Add}
8x = 16
Divide both sides by 8
x = 16/8
x = 2
Plugin x = 2 in equation (A)
3x + z = 0
3*2 + z = 0
6 + z = 0
z = -6
Plug in x = 2 and z = - 6 in equation (I)
-2x +3y - 4z = 8
-2*2 + 3y - 4*(-6) = 8
-4 + 3y + 24 = 8
3y + 20 = 8
3y = 8 - 20
3y = -12
y = -12/3
y = -4
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Answer:
125 deg
Step-by-step explanation:
Keep these three rules in mind:
1) A central angle (vertex is the center of the circle) has the same measure as the arc it intercepts.
2) The measure of an inscribed angle (vertex is point on circle) is half the measure of the intercepted arc.
3) Opposite angles of a rectangle inscribed in a circle are supplementary.
110 deg is a central angle.
By rule 1), the arc intercepted by the central angle 110 deg also measures 110 deg.
a is an inscribed angle that intercepts an arc of 110 deg.
By rule 2), the measure of an inscribed angle is half the measure of the intercepted arc.
angle a measures 55 deg.
Rule 3) Angles a and b are supplementary.
a + b = 180
55 + b = 180
b = 125
Since we can find that the graphs Y value is by a factor of 2 looking at the graph we can find
f(3)=8
It is subtracting the current number by 1/2 OR you can divide by 2. each time.
32 / 2= 16
16 / 2=8
8/2=4
4/2=2
2/2=1
Hope this helped!
That is the definition of a irrational number, A rational number must be able to be written as a ratio of 2 integers. The denominator cannot be 0, because that would make the number undefined
