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ZanzabumX [31]
3 years ago
12

Write 4,570,000 in scientific notation

Mathematics
1 answer:
MrRa [10]3 years ago
5 0

Answer:

4.57 x 10(little 6 lol )

Step-by-step explanation:

4.57 x 10^6

(use the caret symbol [^] to type or write)

4.57E+6

(Scientific E-notation)

4570000

(Real Number)

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A). f(x)=x+3

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How can I do this question
TiliK225 [7]
Hello!

First you have to find the area of the floor

To do this you multiply the sides

4 * 4 = 16

Next you find the area of the rug which is a circle

The equation for this is A = \pi  r^{2}

r is radius

Put in the values you know

A =  \pi 1.5^{2}

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Subtract this by the area of the floor

16 - 7.07 = 8.93

The answer is 8.93m squared

Hope this helps!
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They want you to solve for b​
seropon [69]

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b > -9

Step-by-step explanation:

(-3b > 27) / -3

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3 years ago
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Lesechka [4]

Answer:

a

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The town of Hayward (CA) has about 50,000 registered voters. A political research firm takes a simple random sample of 500 of th
Ilia_Sergeevich [38]

Answer:

(0.0757;0.1403)

Step-by-step explanation:

1) Data given and notation

Republicans =115

Democrats=331

Independents=54

Total= n= 115+331+54=500

\hat p_{ind}=\frac{54}{500}=0.108

Confidence=0.98=98%

2) Formula to use

The population proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

The confidence interval for the population proportion is given by this formula

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

We have the proportion of independents calculated

\hat p_{ind}=\frac{54}{500}=0.108

We can calculate \alpha=1-conf=1-0.98=0.02

And we can find \alpha/2 =0.02/2=0.01, with this value we can find the critical value z_{\alpha/2} using the normal distribution table, excel or a calculator.

On this case z_{\alpha/2}=2.326

3) Calculating the interval

And now we can calculate the interval:

0.108 - 2.326\sqrt{\frac{0.108(1-0.108)}{500}}=0.0757

0.108 + 2.326\sqrt{\frac{0.108(1-0.108)}{500}}=0.1403

So the 98% confidence interval for this case would be:

(0.0757;0.1403)

7 0
3 years ago
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