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NemiM [27]
2 years ago
14

Solve for the value of z in the indices 5z=80z*-1/3

Mathematics
1 answer:
PtichkaEL [24]2 years ago
4 0

z is equal to 0

z = 0

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Find the solution to the system of equations.
goldenfox [79]

Substitute

4x+2=x-4

Then solve

3x=-6

x=-2

Substitute answer into an equation to find y

y=-2-4

y=-6

So you solution is:

(-2,-6)

8 0
3 years ago
-1y + 11= 20 what is the answer 3 or -3
yan [13]

Answer:

-9

Step-by-step explanation:

-1y+11=20

    -11= -11

-1y=20-11

-1y=9

-9

8 0
2 years ago
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I need help right now with homework plz.<br><br>both of them are on the same homework page.
katovenus [111]

Answer:

For the first one I believe it is 90

Step-by-step explanation:

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4 0
3 years ago
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A bag contains 112 red marbles and 100 green marbles. What percent of the marbles are red?
ahrayia [7]

Answer:

Step-by-step explanation:

Total marbles are 212

112/212 = 28/53

Approx. 52. 83%

5 0
3 years ago
Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a
Vikki [24]

Answer:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

Step-by-step explanation:

Information given:

n=131 represent the sample size

\hat p=0.81 represent the estimated proportion

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.326

And replacing into the confidence interval formula we got:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

6 0
3 years ago
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