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Tamiku [17]
4 years ago
14

Neeeddddd helpppp ASAP!!!!!

Mathematics
1 answer:
Artist 52 [7]4 years ago
5 0
The third answer is correct.
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PSYCHO15rus [73]

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3 years ago
a(t)=(t−k)(t−3)(t−6)(t+3) is a polynomial function of tt, where kk is a constant. Given that a(2)=0a(2)=0, what is the absolute
Crank

Since a(2)=0, we know that t-2 must be a factor of a(t), so k=2. Then the zeros of a(t) are t=2,3,6,-3, and their product is -108, whose absolute value is 108.

3 0
3 years ago
15 3/14+ 24 1/14+ 12 2/7+ 12 2/7+ 10 1/7 +10 1/7+ 35 3/7=​
lesantik [10]

Answer:

it is :119.5714

Step-by-step explanation:

15 3/14+24 1/14+12 2/7+12 2/7+10 1/7+10 1/7+35 3/7=

step by step now:

15 3/14+24 1/14+12 4/14+12 4/14+10 2/14+10 2/14+35 6/14=118 22/14=118+1.5714=119.5714

5 0
4 years ago
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