The formula for cosine is adj/hyp. For angle B, 10 is the adjacent and 24 is the opposite. The hypotenuse ( in this case, 26) is the longest side. the ratio for angle b would be 10/26.
Answer:
It would be $2 per piece, because 16 divided by 8 is two.
Step-by-step explanation:
Answer:
10657.5
Step-by-step explanation:
<h2>
Long way that is unnecessarily long</h2>
We can start by finding the area of the larger triangle. Using the Pythagorean theorem, we can say that 251²-105²=the bottom side², and 251²-105²=51976, so the bottom side of the larger triangle is √51976 , or approximately 228. Then, the area of the larger triangle is √51976 * 105/2 = 11969 (approximately). Then, the area of the smallest triangle (the largest triangle - the one that we're trying to find the area of) is 105*(√51976-203)/2 = approximately 1312. Then, subtracting that from the total area, we get (√51976 * 105 - 105*(√51976-203))/2 = 105*203/2 = 10657.5
<h2>Short way</h2>
ALTERNATIVELY, upon further review, we can just see that the height is 105 and the base is 203, so we multiply those two and divide by 2, as is the formula for the area of a triangle, to get 10657.5
ANSWER
X < 9
Solve
2x < - x + 20 + 7
2x < - x + 27 change the signs
2x + x < 27 add the like terms
3x < 27 divide by 3
x < 9
So you have a pole that is 10 feet tall that has a rope that goes from the top to the ground, the rope being 30 degrees to the ground... You can draw a right triangle using these dimensions. Now that you have a triangle, you look at where your 30degree angle is related to the side whose length you know and the side whose length you wish to find. The side you know is opposite from the 30 degrees while the side you want to find is the hypotenuse, for it goes down at an angle. You will use the opposite and hypotenuse sides, so, according to SOH CAH TOA, you will be using sin.

plug in those values and solve for your hypotenuse.
The easiest way to do this is if you knew the identities for special right triangles like the 30 60 90 triangles or the 45 45 90 triangles, but I showed you how to solve for your sides even if they're not special