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MakcuM [25]
3 years ago
6

Jason and Maria are playing a board game in which three dice are tossed to determine a player's move. Find each probability for:

P (two 5s) , P (three 5s) , and P (one 5 or two 5s).
please show work :)
Mathematics
1 answer:
fredd [130]3 years ago
6 0
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,

P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216. 

P(three 5s) = (1 x 1 x 1)/216   = 1/216

P(one 5 or two 5s)  = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
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Answer:

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Step-by-step explanation:

The complete question is attached below .

As given in the attached image

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Step-by-step explanation:

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