Answer:269
Step-by-step explanation:
8x18=144
6x10=60
9x5=45
5x4/2=10
5x4/2=10
144+60+45+10+10=269
Answer:
12 bats
Step-by-step explanation:
Let us number the bat caves from 1 to 45 and divide them into 5 parts:
a) 1
b) 2 to 29 (
bats)
c) 30
d) 31 to 44 (
bats)
e) 45
It is given that any 7 caves in a row has 77 bats. Hence, the total number of bats in part b and d =
bats.
There remains
bats in cave number 1, 30 and 45.
Now, our question demands the maximum possible number of bats in cave 30.
Minimum number of bats in a cave is 2. So we shall put 2 bats in the last cave, which gives us
bats in the first cave.
Therefore, the number of bats in cave number 30 =
bats.
<h2>9x^4 - 6x^2 - 3x - 6</h2><h2 />
(9x^4-13x^3-x-7)+(7x^3-2x+1)
Sort the terms by their powers, as x's with the same powers can be added together:
9x^4
-13x^3 + 7x^3 = -6x^3
-x - 2x = -3x
-7 +1 = -6
<h2>9x^4 - 6x^2 - 3x - 6</h2>
Answer:
8.66 x 10^3
Step-by-step explanation:
8.66 * 1000 (10^3) = 8660