X=35/6 i hope i helped :-)
Answer:
y > 4
Step-by-step explanation:
2 (5y-4)>32
Divide each side by 2
2/2 (5y-4)>32/2
5y-4 > 16
Add 4 to each side
5y-4+4 > 16+4
5y > 20
Divide each side by 5
5y/5 > 20/5
y > 4
Answer:
2
Step-by-step explanation:
4/2=2
To find y, divide the first equation by 2.
y = 4
To find x, use that value for y in the second equation. Add 4, then divide by 2.
15·4 = 2x -4
60 +4 = 2x
64/2 = x = 32
The solution is (x, y) = (32, 4).
Answer:
We are effectively looking for a and b such that 5, a, b, 135 is a geometric sequence.
This sequence has common ratio <span><span>3<span>√<span>1355</span></span></span>=3</span>, hence <span>a=15</span> and <span>b=45</span>
Explanation:
In a geometric sequence, each intermediate term is the geometric mean of the term before it and the term after it.
So we want to find a and b such that 5, a, b, 135 is a geometric sequence.
If the common ratio is r then:
<span><span>a=5r</span><span>b=ar=5<span>r2</span></span><span>135=br=5<span>r3</span></span></span>
Hence <span><span>r3</span>=<span>1355</span>=27</span>, so <span>r=<span>3<span>√27</span></span>=3</span>
Then <span>a=5r=15</span> and <span>b=ar=15⋅3=45</span>