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stellarik [79]
3 years ago
5

A crate is 3 fourth yard long and 2 third yard wide. The crate is also 2 feet tall. What is the area of the top of the crate?

Mathematics
1 answer:
True [87]3 years ago
8 0
L*W
6 yards is the answer
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In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=26°, and QO = 4.9 feet. Find the length of PQ to the nearest tenth of a foot.
Step2247 [10]

Given:

In ΔOPQ, m∠Q=90°, m∠O=26°, and QO = 4.9 feet.

To find:

The measure of side PQ.

Solution:

In ΔOPQ,

m\angle O+m\angle P+m\angle Q=180^\circ        [Angle sum property]

26^\circ+m\angle P+90^\circ=180^\circ

m\angle P+116^\circ=180^\circ

m\angle P=180^\circ -116^\circ

m\angle P=64^\circ

According to Law of Sines, we get

\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}

Using the Law of Sines, we get

\dfrac{p}{\sin P}=\dfrac{o}{\sin O}

\dfrac{QO}{\sin P}=\dfrac{PQ}{\sin O}

Substituting the given values, we get

\dfrac{4.9}{\sin (64^\circ)}=\dfrac{PQ}{\sin (26^\circ)}

\dfrac{4.9}{0.89879}=\dfrac{PQ}{0.43837}

\dfrac{4.9}{0.89879}\times 0.43837=PQ

2.38989=PQ

Approximate the value to the nearest tenth of a foot.

PQ\approx 2.4

Therefore, the length of PQ is 2.4 ft.

4 0
3 years ago
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