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3 years ago

Please help. What is the interquartile range for the data set? 27, 4, 54, 78, 27, 48, 79, 64, 5, 6, 41, 71

Mathematics

1 answer:

mylen [45]3 years ago

4 0

You cant you need to give a picture of where Q1 Q2 Q3 Q4 are if not we cannot solve for you sorry

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Gcf of 12 and 15 please help me.......

aivan3 [116]

Answer:3

Step-by-step explanation:the answer is 3 I did the math

5 0

3 years ago

the length of rectangle is 4cm more than its breadth and its perimeter is11cm more than its .The area of the rectangle

Kisachek [45]

We can mark "breadth" as x so lenght will be x +4 so x+x+x+2+x+2 =11
Therefore 4x+4=11
4x=7
X=7/4
So length is x+4 =7/4 +4

7 0

3 years ago

361.2 ÷ ________ = 036.12 (3 points)

Goryan [66]

Answer:

C. 10

Step-by-step explanation:

You can take the blank as x

so 361.2 / x = 36.12

multiply by x

361.2 = 36.12x

divide

x = 10

7 0

3 years ago

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Kevin has a stack of newspapers. Each one weighs 15 pounds. The entire stack weighs 4

Ratling [72]

Answer:7

Step-by-step explanation:

8 0

3 years ago

The equation a = StartFraction one-half EndFraction left-parenthesis b 1 plus b 1 right-parenthesis.(b1 + b2)h can be used to de

aleksley [76]

Answer:

The equivalent expressions are:

$b1=\frac{2a}{h}-b2$

$h=\frac{2a}{b1+b2}$

Step-by-step explanation:

Given equation for finding area of a trapezoid:

$a=\frac{1}{2}(b1+b2)h\\$

where $a$ represents area, $h$ represents height and $b1\ and\ b2$ represents the base lengths of the trapezoid.

Evaluating $h$ by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

$2\times a=2\times\frac{1}{2}(b1+b2)h$

$2a=(b1+b2)h$

Dividing both sides by $b1+b2$

$\frac{2a}{b1+b2}=\frac{(b1+b2)h}{b1+b2}$

$\frac{2a}{b1+b2}=h$

$\therefore h=\frac{2a}{b1+b2}$

Evaluating $b1$ by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

$2\times a=2\times\frac{1}{2}(b1+b2)h$

$2a=(b1+b2)h$

Dividing both sides by $h$

$\frac{2a}{h}=\frac{(b1+b2)h}{h}$

$\frac{2a}{h}=b1+b2$

Subtracting both sides by $b2$

$\frac{2a}{h}-b2=b1+b2-b2$

$\frac{2a}{h}-b2=b1$

$\therefore b1=\frac{2a}{h}-b2$

8 0

3 years ago

Read 2 more answers