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sveticcg [70]
4 years ago
14

PLZ HELP WILL GIVE BRAINLIEST!!!!!!!

Mathematics
2 answers:
Novosadov [1.4K]4 years ago
6 0
Anyone could be chosen but the highest possibility of chosen marble is red due to the percentage of marbles in bag being red.
Sergeeva-Olga [200]4 years ago
4 0
The best possibility is red since there are 15 you have a higher possibility
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Consider that the length of rectangle A is 10 cm and its width is 6 cm. Which rectangle is similar to rectangle A?
Rom4ik [11]

Answer: B

15cm and 9cm

Step-by-step explanation:

7 0
3 years ago
30 points: 5 star and best answer and thanks. you can leave answers in. A B C or D ty ty ty.
nalin [4]
1, B 2, C 3, C 4, C 5, a 6, b 7, b 8, C 9, a I think. Hoped this helps.
5 0
4 years ago
Read 2 more answers
Which linear inequality is represented by the graph?<br> 0214<br> Qys<br> ovas<br> 2x + 3
Luba_88 [7]

Answer:

sorry I just needed points

Step-by-step explanation:

dndjdjdnsnsnsuxknsdu djdjebheu suss hsshsb yshebejdb usjsne

8 0
3 years ago
If you start with 85 milligrams of Chromium 51, used to track red blood cells, which
zysi [14]

About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes (m), measured in milligrams, decreases exponentially in time (t), measured in days. The model that represents such decrease is described below:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

  • m_{o} - Initial mass, in milligrams.
  • m(t) - Current mass, in milligrams.
  • \tau - Time constant, in days.

In addition, the time constant is defined in terms of half-life (t_{1/2}), in days:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m_{o} = 85\,mg, t_{1/2} = 27.7\,d and m(t) = 8.5\,mg, then the time required for decaying is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{27.7\,d}{\ln 2}

\tau \approx 39.963\,d

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}

t\approx 92.018\,d

About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

8 0
3 years ago
86 teams enter the race .if the race begins with 16 dogs on each team how many dogs will enter the race
brilliants [131]

Answer:

1376 dogs

Step-by-step explanation:

This is just a multiplication problem if we convert the words to mathematical formulas.

There are 86 teams: a_1,a_2,...a_8_5,a_8_6. Each team has 16 dogs: a_1=16,a_2=16,...a_8_5=16,a_8_6=16.

So, we can add up 16 to itself 86 times, which is just 16 * 86 = 1376

Thus, the answer is 1376 dogs.

Hope this helps!

5 0
3 years ago
Read 2 more answers
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