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Akimi4 [234]
2 years ago
15

It takes Dimitri 9 minutes to make a simple bracelet and 20 minutes to make a deluxe bracelet. He has been making bracelets for

longer than 120 minutes. If x represents the number of simple bracelets that he has made and y represents the number of deluxe bracelets he has made, the inequality 9x + 20y > 120 represents the scenario. Which is a possible combination of bracelets that Dimitri may have made? 3 simple bracelets and 4 deluxe bracelets 0 simple bracelets and 6 deluxe bracelets 12 simple bracelets and 0 deluxe bracelets 7 simple bracelets and 3 deluxe bracelets
Mathematics
2 answers:
frosja888 [35]2 years ago
7 0
Last one 7 and 3
9(7)+20(3)>120
63+ 60
123>120
Says 123 minutes is longer than 120 that's why it is that answer
stepladder [879]2 years ago
7 0
1st case ,  27 + 80 = 107 > 120  incorrect

2nd case, 0+ 120 = 120 > 120  , incorrect

3rd case, 108 + 0 =108 > 120 , incorrect

4th case, 84 + 60 = 144 > 120 , correct

so, option d) 7 simple bracelets and 3 deluxe bracelets

hope it helped a bit
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Consider the following example:

5 can also be written as 5x^{0}. Any variable raised to power 0 is equal to 1. So x raised to power 0 is equivalent to multiplying by 1, it leaves the expression/number unchanged. 

So yes, polynomial of degree zero is a constant term
7 0
3 years ago
Find the sum of the geometric sequence. 1, one divided by two, one divided by four, one divided by eight, one divided by sixteen
igomit [66]
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5 0
3 years ago
Read 2 more answers
F(x)=-2x+3 how do you find x if f(x) = 11
NeX [460]
Since we know f(x)=11 all we need to do is substitute and solve. so
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5 0
3 years ago
A rectangular piece of metal is 30 in longer than it is wide. Squares with sides 6 in long are cut from the four corners and the
Alexandra [31]

Answer:

length=53 in

width= 23 in

Step-by-step explanation:

First, we know that each corner has now a square of 6 in long, so the heigth of the box will be of this size (as you can see in the picture attached). Then, the length and the width of the box would be the same as the piece, but with 12 in less. Therefore the equations to solve the problem are:

h=6 in\\w=x-12\\l=x+30-12\\l=x+18\\\\V: volume of the box\\V=6*(x-12)*(x+18)\\2706=6x^{2}+36x-1296\\0=6x^{2}+36x-4002\\\\

We factorize the 6 and we get:

0=x^{2}+6x-667\\

Finally we solve for x, and we get the initial dimensions of the piece of metal:

x=23l=30+x=30+23=53 in\\w=x= 23 in

7 0
3 years ago
An elevator has a placard stating that the maximum capacity is 1296 lb long dash — 8 passengers.​ So, 8 adult male passengers ca
Masja [62]

Answer:

There is a 98.26% probability that it is overloaded.

This elevator does not appear to be safe.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of males are normally distributed with a mean of 170 lb, so \mu = 170

They have a standard deviation of standard deviation of 29 lb, so \sigma = 29.

We have a sample of 8 adults, so we have to find the standard deviation of the sample to use in the place of \sigma in the Z score formula.

s = \frac{\sigma}{8} = \frac{29}{8} = 3.625

Find the probability that it is overloaded because they have a mean weight greater than 162 lb, so X = 162

Z = \frac{X - \mu}{\sigma}

Z = \frac{162 - 170}{3.625}

Z = -2.21

Z = -2.21 has a pvalue 0.0174.

So, there is a 1-0.0174 = 0.9826 = 98.26% probability that it is overloaded.

Any probability that is above 95% is considerer unusually high. So, this elevator does not appear to be safe, since there is a 98.26% probability that it is overloaded.

8 0
2 years ago
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