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lina2011 [118]
3 years ago
6

Graph the following points on the graphing calculator:

Mathematics
2 answers:
KiRa [710]3 years ago
7 0

The pattern is min-zero-max-zero-min, which is the pattern for a cosine function of the form y = acos(x) + k, but is reflected over the x-axis (so a < 0).

The amplitude is |a|, so a = –1 and |a| = 1.

The midline is exactly between the max and the min, y = (6 + 8)/2 = 7, so k = 7.

The equation is y = –cos(x) + 7.

Lerok [7]3 years ago
5 0
We are given the following coordinates: 

(0,6), (π/2, 7); (π, 8); (3π/2, 7); and (2π, 6)

If we graph these points, we will observe that the function is a cosine function. Since the function does not pass through the origin. Instead, it has a y-intercept equal to 6.  <span />
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HELP ASAP.<br><br> Please solve.<br><br> 2 plus or minus the square root of negative 36 over 2
AVprozaik [17]

Answer:

The expression is not defined in a set of real numbers.

The square root of a negative number is not defined in the set of real numbers.

5 0
3 years ago
CD has endpoints C(-3, 4) and D(1, -2). Find the coordinates<br> of its midpoint.
Natalija [7]

Answer:

Midpoint (-1 , 1)

Step-by-step explanation:

Formula: (midpoint)

Let the point A(x , y) be the midpoint of CD.

x=\frac{x_c+x_D}{2} =\frac{-3+1}{2} =\frac{-2}{2} =-1

y=\frac{x_C + y_D}{2} =\frac{4+(-2)}{2} =\frac{2}{2} =1

Then

A(-1 , 1)

4 0
2 years ago
Read 2 more answers
The diagram below represents the net of a triangular prism. What is the surface area of the triangular prism?
AleksandrR [38]

Answer:

(C)

Step-by-step explanation:

The diagram is divided ninto 5 parts that is rectangles ABCD, CHGD, GFEH and  triangles CIH and DGJ.

Area of rectangle ABCD= l{\times}b

=12{\times}6=72cm^{2}

Area rectangle CDHG=  l{\times}b

=12{\times}8=96cm^{2}

Area rectangle HGFE= l{\times}b

=10{\times}12=120cm^{2}

Area of triangles CIH and DIG= 2{\times}\frac{1}{2}{\times}b{\times}h

=6{\times}8=48cm^{2}

Surface area of the triangular prism=Area of rectangle ABCD+Area rectangle CDHG+Area rectangle HGFE+Area of triangles CIH and DIG

=72+96+120+48=336cm^{2}

Hence, option C is correct.

3 0
3 years ago
The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar
mafiozo [28]

Answer:

Ratio = \frac{R^2 - r^2 }{ r^2}

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

Area = \frac{\theta}{360}\pi r^2

For the inner circle

r \to radius

The sector of the inner circle has the following area

A_1 = \frac{\theta}{360}\pi r^2

For the whole circle

R \to Radius

The sector of the outer sector has the following area

A_2 = \frac{\theta}{360}\pi (R^2 - r^2)

So, the ratio of the outer sector to the inner sector is:

Ratio = A_2 : A_1

Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2

Cancel out common factor

Ratio = R^2 - r^2 : r^2

Express as fraction

Ratio = \frac{R^2 - r^2 }{ r^2}

6 0
2 years ago
Can you please solve this as soon as you can? Thank you!
lesya692 [45]

Step-by-step explanation:

x=120⁰

hdbdbdddfhcydhgdjvds

5 0
3 years ago
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