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frozen [14]
3 years ago
7

How much heat will be absorbed by a 63.1 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°

C to 67.0°C?
Chemistry
1 answer:
cluponka [151]3 years ago
4 0

Answer:

Q=2582J=2.58kJ

Explanation:

Hello,

In this case, for us to compute the absorbed heat, we apply the following equation:

Q=m_{Al}Cp_{Al}(T_2-T_1)

Whereas we use the mass, specific heat and temperature change for the piece of aluminium, thus, we obtain:

Q=63.1g*0.930\frac{J}{g*\°C}*(67.0-23.0)\°C\\ \\Q=2582J=2.58kJ

It is positive as the heat is entering, therefore the temperature raises.

Best regards.

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