Answer: The loser's card shows 6.
Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
4 3
5 3
6 2
6 3
9 2
12 1
15 1
18 1
Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
6 2
6 3
Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.
2 6
3 6
Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
Answer:
26
Step-by-step explanation:
Sydney = x
Devaughn = 2x
x + 2x = 78
3x = 78
x = 78 / 3
x = 26
Hope that helps!
Answer:
0.8
Step-by-step explanation:
multiply 1.00 .20 4 times
Answer:
123
Step-by-step explanation:
s=-2
-15s^2-9(-5+s)
=-15s^2+45-9s
=-15s^2-9s+45
=15(-2)^2-9×(-2)+45
=15×4+18+45
=60+18+45
=123
I think E but I’m probably wrong???
