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3 years ago

Why do people in jonas's community have the same birthday?

1 answer:

3 0

Everyone was not born in the same day but they do not celebrate birthdays like us. Every year they move the class of children who were born in the same year up together. This means that all of the babies who are recognized as Ones will be recognized as Twos together, and then Threes in another year.

Since the babies are not all the same age biologically, some kids have an advantage.

Some were already walking, wobbly on their unsteady legs; others were no more than a few days old, wrapped in blankets, held by their Nurturers. (ch 2, p. 11)

Although it is claimed that the differences disappear by the time they are school age, there might be some advantage to being an older One versus a younger One. Jonas was a little bit older, and he notes that it had given him a “slight advantage” when he was younger (ch 7, p. 50). Since he is more sensitive and mature than the others, perhaps the advantage was not slight or temporary.

There are fifty children born each year. They are given numbers from 1 to 50. Their parents refer to them by number and not by name whenever they are frustrated with them, kind of like how our parents call their children by their full names.

Sometimes parents used them in irritation at a child's misbehavior, indicating that mischief made one unworthy of a name. (ch 7, p. 50)

For this reason, kids may not like hearing their numbers. However, having a number is just part of their lives. Since they are taught from a young age to not value individuality, it would not concern them to have a number.

The use of numbers and the abandonment of birthdays were both attempts by the community to institute Sameness. This way, no one is singled out. No one person is celebrated, except when the Ceremony of Twelve gives them assignments. Everyone works for the good of the community, and the self is unimportant.

i read this book a lot so I mentioned the pg

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When enabling IPsec mobile client support, you made some selections in the Xauth section of the interface. What does Xauth stand

konstantin123 [22]

Answer:

Extended authentication

Explanation:

Xauth = Extended authentication

An extended authentication can cause security to be increased because it requires the user to enter a username and password. These details would then be authenticated at the internal database of the controller. This extension is an ipsec extension which would enable VPN users to enter a username and password. These details would be required of the user while trying to connect and they would be checked against the login details registered by such a user.

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4 years ago

Implement a method called bubbleSort, that takes an ArrayList, sorts it using bubble sort algorithm, and returns a sorted list;

boyakko [2]

Answer:

Java algorithm is given below

Explanation:

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Random;

public class Temp {

static void bubbleSort(ArrayList<Integer> list) {

int n = list.size();

for (int p = 0; p < n - 1; p++)

for (int q = 0; q < n - p - 1; q++)

if (list.get(q) > list.get(q + 1)) {

int temp = list.get(q);

list.set(q, list.get(q + 1));

list.set(q + 1, temp);

}

static void selectionSort(ArrayList<Integer> list) {

int n = list.size();

for (int p = 0; p < n - 1; p++) {

int minimumIndex = p;

for (int q = p + 1; q < n; q++)

if (list.get(q) < list.get(minimumIndex))

minimumIndex = q;

int temp = list.get(p);

list.set(p, list.get(minimumIndex));

list.set(minimumIndex, temp);

}

static void insertionSort(ArrayList<Integer> list) {

int size = list.size();

int p, val, q;

for (p = 1; p < size; p++) {

val = list.get(p);

q = p - 1;

while (q >= 0 && list.get(q) > val) {

list.set(q + 1, list.get(q));

q = q - 1;

}

list.set(q + 1, val);

}

static void mergeSort(ArrayList<Integer> list, int low, int high) {

if (low < high && (high - low) >= 1) {

int mid = (high + low) / 2;

mergeSort(list, low, mid);

mergeSort(list, mid + 1, high);

merger(list, low, mid, high);

}

static void merger(ArrayList<Integer> list, int low, int mid, int high) {

ArrayList<Integer> mergedArray = new ArrayList<Integer>();

int left = low;

int right = mid + 1;

while (left <= mid && right <= high) {

if (list.get(left) <= list.get(right)) {

mergedArray.add(list.get(left));

left++;

} else {

mergedArray.add(list.get(right));

right++;

}

while (left <= mid) {

mergedArray.add(list.get(left));

left++;

}

while (right <= high) {

mergedArray.add(list.get(right));

right++;

}

int i = 0;

int j = low;

while (i < mergedArray.size()) {

list.set(j, mergedArray.get(i++));

j++;

}

public static void main(String[] args) throws Exception {

ArrayList<Integer> list = new ArrayList<>();

Random rand = new Random(System.currentTimeMillis());

for (int i = 0; i < 10000; i++) {

list.add(rand.nextInt(256));

}

long start = System.currentTimeMillis();

selectionSort(list);

int sel = (int) (System.currentTimeMillis() - start);

System.out.println("Selection Sort time (in ms): " + sel);

list.clear();

// ------------------------

rand = new Random(System.currentTimeMillis());

for (int i = 0; i < 10000; i++) {

list.add(rand.nextInt(256));

}

start = System.currentTimeMillis();

insertionSort(list);

int ins = (int) (System.currentTimeMillis() - start);

System.out.println("Insertion Sort time (in ms): " + ins);

list.clear();

// ------------------------

rand = new Random(System.currentTimeMillis());

for (int i = 0; i < 10000; i++) {

list.add(rand.nextInt(256));

}

start = System.currentTimeMillis();

bubbleSort(list);

int bub = (int) (System.currentTimeMillis() - start);

System.out.println("Bubble Sort time (in ms): " + bub);

list.clear();

// ---------------------------

rand = new Random(System.currentTimeMillis());

for (int i = 0; i < 10000; i++) {

list.add(rand.nextInt(256));

}

start = System.currentTimeMillis();

mergeSort(list, 0, list.size() - 1);

int mer = (int) (System.currentTimeMillis() - start);

System.out.println("Merge Sort time (in ms): " + mer);

long m = Math.min(Math.min(sel, ins), Math.min(bub, mer));

if (m == sel)

System.out.println("Selection Sort is fastest");

else if (m == ins)

System.out.println("insertion Sort is fastest");

else if (mer == m)

System.out.println("Merge Sort is fastest");

else if (m == bub)

System.out.println("Bubble Sort is fastest");

}

6 0

3 years ago

A user is trying to delete a file located on an NTFS volume on his Windows 8 computer but is unable to do so. Why is this?

Molodets [167]

There can be several reasons why the user is not able to delete a file on the NTFS Volume or disk partition of the computer. Possible scenarios are as follows.

1. The user does not have sufficient permission to perform the task as the file itself may not be owned with the user. The best way is to make sure the user is an administrator.

2. The file is corrupted which prevents to properly access, running a chkdsk will help to validate with this.

3. Another common scenario is that the file is actually currently in use.

4 0

3 years ago

HELP PLEASE!!! Which development method is best explained in this way: a creation of a prototype model that will eventually be d

DerKrebs [107]

Answer:

Not sure but I think its Rapid Prototyping Method

4 0

3 years ago

Joe, an end-user, reports that the Windows PC he is using automatically locks when he leaves his desk and walks to a printer to

ivann1987 [24]

Answer:

A. Domain-level group policies

Explanation:

Because domain-level polices are automatically implement all users that are login on the PC and PC is connect to the domain. From domain polices you can set what user can open and what can not open, Joe Windows PC he is using automatically locks also through domain policy, Administrator set the time when any end-user leave their PC automatically after the time set administrator screen saver run and asked password of that user to return back in the windows.

6 0

3 years ago