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dolphi86 [110]
3 years ago
14

Numa caixa ha 8 bolas verdes ,5 bolas vermelhas e 2 bolas azuis. Tira se ao acaso uma bola da caixa. Calcula a probabilidade da

bola saida ser: verde ; vermelho; azul : verde ou azul; nao verde
Mathematics
1 answer:
hichkok12 [17]3 years ago
4 0

Responda:

P (verde) = 8/15

P (vermelho) = 1/3

P (azul)). 2/15

P (verde ou azul) = 2/3

P (não verde) = 7/15

Explicação passo a passo:

Dado o seguinte:

Número de bolas verdes = 8

Número de bolas vermelhas = 5

Número de bolas azuis = 2

N (verde) = 8

N (vermelho) = 5

N (azul) = 2

Portanto, número total de bolas;

N (total) = 8 + 5 + 2 = 15

Probabilidade = número de resultados requeridos / Total de resultados possíveis

1.) Probabilidade de escolher uma bola verde:

P (verde) = número de bolas verdes / número total de bolas

P (verde) = 8/15

2.) Probabilidade de pegar uma bola vermelha: P (vermelho) = número de bolas vermelhas / número total de bolas

P (vermelho) = 5/15 = 1/3

3) Probabilidade de pegar uma bola azul:

P (azul) = número de bolas azuis / número total de bolas

P (azul) = 2/15

4) probabilidade de verde ou azul:

P (verde ou azul) = P (verde) + p (azul)

P (verde ou azul) = 15/8 + 2/15 = 10/15 = 2/3

P (não verde) = 1 - P (verde)

P (não verde) = 1-8/15

P (não verde) = 7/15

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