Question

The graph below represents which systems of inequalities?

Answer 1

Answer:

y ≤ x + 3

y ≤ -2x + 3

Step-by-step explanation:

Graph attached shows two solid lines having equal y-intercepts as 3 units.

Since one line passes through two points (0, 3) and (-3, 0),

Slope of this line 'm' = $\frac{y_2-y_1}{x_2-x_1}$

                                  = $\frac{3-0}{0+3}$

                                  = 1

Let the equation of the this line is,

y = mx + b

where m = slope of the line

b = y-intercept

Therefore, equation of the line having slope = 1 and y-intercept = 3 units,

y = 1.x + 3

y = x + 3

Since, shaded region shown is on the left of the line y = x + 3

Therefore, y ≤ x + 3 will be the inequality with shaded area in green.

Slope of the second line passing through (0, 3) and (1.5, 0)

m' = $\frac{3-0}{0-1.5}$

    = -2

Therefore, equation of the second line will be,

y = (-2)x + 3

y = -2x + 3

Since shade area (In yellow) is below the given solid line, equation of the inequality will be,

y ≤ -2x + 3