G(C)=c(4c+8)(c-1) which values are equal to 0?

Arte-miy333 [17]

This is a simple Pythagorean Theorem problem. 7 is the hypotenuse so you would do c^2-a^2=b^2. In this case 7^2-2^2=b^2. 7^2 is 49 and 2^2 is 4 so you have 49-4=b^2. 49-4 is 45. The square root of 45 is 6.70. So x=6.70

8 0

3 years ago

Ms. jada wants to save money for her spring break trip. She already has $400 saved in her account. She needs $1600 for the entir

valkas [14]

Answer:

1600-400

=1200

1200/300

=4 months

3 0

3 years ago

Read 2 more answers

How to slove this question 7v-v=12

vampirchik [111]

7v-v=12 subtract v from 7v to get 6v
6v=12 divide 12 by 6 to find variable
v=2

5 0

4 years ago

For a club gathering you were having, you bought a total of 50 burgers, and spent $90. You paid $2 per turkey burger, and $1.50

Sedaia [141]

Answer:

No. You would have to cut the number of veggie burgers in more than half.

Explanation:

1. Model the situation with a system of equations

a) Name the variables:

number of turkey burgers: t
number of veggie burgers: v

b) Number of burgers:

50 = t + v

c) Cost of the 50 burgers:

$90 = 2t + 1.50v

2. Solve that system of equations:

a) System

50 = t + v

90 = 2t + 1.50v

b) Mutliply the first equation by 2 and subtract the second equation

100 = 2t + 2v
90 = 2t + 1.50v

10 = 0.5v

v = 20 ⇒ t = 50 - 20 = 30

c) How much would you spend if the next year you buy the double of 20 turkey burgers (40) and the half of 30 veggie burgers (15)

$2(40) + $1.50(15) = $80 + $22.50 = $102.50

Then, you if you double the number of turkey burgers, and cut the number burgers in half, you would spend more than $90 ($102.50).

6 0

4 years ago

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function $f(x)=(x^{2},4x,z^{2})$ and curve C is ellipse of equation

$16x^{2} + 4y^{2} = 3$

Theory: Stokes Theorem is given by:

$I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx$

Where, Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Also, f(x) = (F1,F2,F3)

$\hat{N} = grad(g(x))$

Using Stokes Theorem,

Surface is given by g(x) = $16x^{2} + 4y^{2} - 3$

Therefore, tex]\hat{N} = grad(g(x))[/tex]

$\hat{N} = grad(16x^{2} + 4y^{2} - 3)$

$\hat{N} = (32x,8y,0)$

Now, $f(x)=(x^{2},4x,z^{2})$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]$

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

$I= \int \int\limits {Curl f\cdot \hat{N} } \, dx$

$I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx$

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0

3 years ago