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3 years ago

G(C)=c(4c+8)(c-1) which values are equal to 0?

Mathematics

1 answer:

VashaNatasha [74]3 years ago

4 0

Answer:

am is well ha all ha FL ha FL of all of all to the ell week of

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Someone please help me with this!

Sveta_85 [38]

5(14-2)^2/2

5( 12)^2/2

Do the exponent

5(12*12)/2

5(144)/2

144/2= 72

72*5= 360

Answer : 360

8 0

3 years ago

The force (F) needed to cause the acceleration (a) of an object of mass, m, is given by the equation, F=ma where m is the object

KATRIN_1 [288]

From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;

F = ma

In this case, m = 5kg, a = 6m/s^2 and we want to find F

F = 5 x 6

F = 30N

Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.

8 0

3 years ago

PLEASE HELP !!!!! ASAP

Anna71 [15]

Well, the first ballon appears to be halfway to the second (the second being 300 meters from the ground) so the first, being at approximately 150 meters, both away from the ground and the balloon, would have to travel a further 150 meters.

8 0

3 years ago

What is the area of the shaded triangle inside the square? Round your answer to the nearest square inch.

Semenov [28]

Answer:

Step-by-step explanation:

1243

3 0

2 years ago

Read 2 more answers

12. An equation is shown. 8 1/2 - 3 1/? = 5 3/12<br>What is the value of the missing number?

weeeeeb [17]

Answer:

Step-by-step explanation:

Alright, lets get started.

$8\frac{1}{2}-3\frac{1}{?}=5\frac{3}{12}$

These are mixed number given.

Suppose the complete mixed number of second place is x.

Converting mixed numbers into fractions.

$\frac{17}{2}-x=\frac{63}{12}$

Adding x in both sides

$\frac{17}{2}=x+\frac{63}{12}$

$x=\frac{17}{2}-\frac{63}{12}$

Making common denominator

$x=\frac{102}{12}-\frac{63}{12}$

$x=\frac{39}{12}$

$x=\frac{13}{4}$

In mixed number form:

$x=3\frac{1}{4}$

So comparing with given equation, the '?' sign will be equal to 4.

Hence the answer is 4 : Answer

Hope it will help :)

4 0

3 years ago