Look at the picture.
The polygon is a right-angled trapezoid.
The area is:

The points (-2,-1) and (6,-1) lie on the same horizontal line, so the distance between them is 6-(-2)=6+2=8. The length of a is 8 units.
The points (-2,5) and (3,5) lie on the same horizontal line, so the distance between them is 3-(-2)=3+2=5. The length of b is 5 units.
The points (-2,5) and (-2,-1) lie on the same vertical line, so the distance between them is 5-(-1)=5+1=6. The length of h is 6 units.

The area is
39 square units.
The point
is on the graph of the equation.
Explanation:
The equation is 
We need to determine the point
is on the graph.
To determine the point
is on the graph, we need to substitute the point in the equation and find whether the LHS is equal to RHS.
Thus, substituting the point
in the equation
, we get,

Multiplying the terms within the bracket, we have,

Adding the LHS, we have,

Thus, both sides of the equation are equal.
Hence, the point
is on the graph of the equation 
Answer:
g(x)=-x-5
Step-by-step explanation:
Simplify parenthesis by distribution:
g(x)=-x-3+2-4
Addition and Subtraction:
-3+2=-1, -1-4=-5
Finalize since no more simplification:
g(x)=-x-5
Pls give thx and brainliest wanna level up
Y = -0.4x
1) It is a straight line
2) I passes through the origin (0,0), because the y-intercpet is 0.
3) The slope is negative, so it passes throuh II and III quadrants
4) The magnitude of the slope = 0.4
4) The angle of the line with the negative side of the x-axis is that whose tan is 0.4 => angle = 21.8 °
With all that information you can identify the graph, given that you didn't include the options.