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3 years ago

john started homework at 7:00 pm he finish at 3:00 then he checked double the amount last time how much time did he spend

1 answer:

8 0

K, so am assuming of th next day

from 7pm to 12 midnight is 5 hours
from 12 midnight so 3am is 3 hours
3+5=8

8 hours total

checked double the amoutn last time
he spent 16 hours last time?

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Three is no more than the difference of seven times a number P and 13

eduard

Answer:

7x(3 13)

Step-by-step explanation:

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3 years ago

Molly scored 86, 87, 93, and x

zmey [24]

Answer:

Step-by-step explanation:

Average is the sum of all data points divided the number of data points.

In this specific situation, the average test score, 91, is equal to the sum of Molly's four individual test scores divided by the number of test Molly had, 4.

(( 86 + 87 + 93 + x) / 4) = 91

86 + 87 + 93 + x = 91/4

86 + 87 + 93 + x = 364

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3 years ago

Which statement is true when 3.4 is placed in the blank? 10.2 ÷ ___ = 0.3 20.4 ÷ 6 = ___ 27.2 ÷ ___ = 0.8 30.6 ÷ 0.9 = ___

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Step-by-step explanation:

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3 years ago

Read 2 more answers

(11) U

monitta

Answer:

More clarification

Step-by-step explanation:

2 of a white ball =2/30 =1/15;

This is the probability of picking a black ball.

Let the number of black ball be X

x/(x +20)= 1/15[ probability of picking black ball ]

15x = x + 20 ; by cross multiplication

14x=20; x = 20/ 14 =1.42 = 1 [ approximately]

But to satisfy the premise given above; we have to approximate the no of balls to 2

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4 years ago

Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation option

denis-greek [22]

Answer:

The probability that he teleports at least once a day = $\mathbf{\frac{5}{9}}$

Step-by-step explanation:

Given -

Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation options teleport ride a dragon or walk to work and in the evening he has the same three choices for his trip home.

Total no of outcomes = 3

P( He not choose teleport in the morning ) = $\frac{2}{3}$

P( He not choose teleport in the evening ) = $\frac{2}{3}$

P ( he choose teleports at least once a day ) = 1 - P ( he not choose teleports in a day )

= 1 - P( He not choose teleport in the morning ) $\times$ P( He not choose teleport in the evening )

= $1 - \frac{2}{3}\times\frac{2}{3}$

= $\frac{5}{9}$

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3 years ago