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AURORKA [14]
3 years ago
11

What is the value of b so that the equation x^2+bx+5=0 will have x intercepts (-5,0) and (-1,0)

Mathematics
1 answer:
storchak [24]3 years ago
6 0
Plug one intercepts: (-1)^2+(-1)b+5=0
(-5)^2+(-5)b+5=0
simplify: 6-b=0
30-5b=0
solve for b: 6=b
30/5=b
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Step-by-step explanation:

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We can use linear combinations of the equations to eliminate variables.

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Q18 Answer: (7,5)

y = -3x + 5
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4y +1(5x - 4y) = 4(-3x + 5) + 1(-3)

5x = -12x + 20 -3

17 x = 17

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Q19 Answer (1,2)

6x + 5y = 25
x = 2y + 24
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Q20 Answer (10,-7)


3x + y = 18
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9x  + 3y = 54
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Check: 3(4)+6=18 good,  -7(4)+3(6)=-10 good

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3 years ago
Please help with solving
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Meaning M.N also has to be 4
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N.P = 6
0.P = 2
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Answer:

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Step-by-step explanation:

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