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3 years ago

Find the value of this expression if x = -9

Mathematics

2 answers:

ASHA 777 [7]3 years ago

5 0

The creepy and the crawly = -15. You are very welcome. DUN DUN DUN DUN.

tatyana61 [14]3 years ago

4 0

Answer:

-15

Step-by-step explanation:

(-9)^2+9/-9+3

81+9/-6

90/-6

-15

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What is 3+0.75x=5.25-0.25 equal?

s2008m [1.1K]

3 + 0.75x = 5.25 - 0.25x

0.75x = 2.25 - 0.25x

x = 2.25

3 + 0.75(2.25) = 5.25 - 0.25(2.25)

3 + 1.6875 = 5.25 - 0.5625

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They are equal

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2 years ago

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What is the slope-intercept equation of the line below?

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3 years ago

Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩

klemol [59]

$\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle$

$\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt$

$\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle$

$\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1$

$\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2$

$\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3$

With the initial condition $\mathbf r(0)=\langle4,6,3\rangle$ , we find

$\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9$

$\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6$

$\dfrac92\cdot0^2+C_3=3\implies C_3=3$

So the particular solution to the IVP is

$\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle$

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3 years ago

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elixir [45]

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3 years ago