I guess i might ask a random question for once<br><br> How many half of days are there in a year?

You are driving 2760 miles across the country. During the first 3 days of your trip, you drive 1380 miles. If you continue to dr

prohojiy [21]

The entire trip will take 6 days.

(Encircle this answer, as said on the directions)

Step-by-step explanation:

We know that the first three days of the trip, we traveled 1380 miles.

Find the UNIT RATE of MILES PER day:

1380/3 = 460

Unit rate = 460 miles per day

If we were to drive at this (460 mi per day) rate EACH day and the whole journey takes 2760 miles across the country.

FInd the NUMBER of DAYS of the ENTIRE TRIP:

2760/460 = 6

It will take us 6 days to drive to the destination.

5 0

2 years ago

Which is 144 written as a power of a number

s2008m [1.1K]

12^2 What is it's square root or basically you could divide it so it's 12 to the power of 2 or 12^2

5 0

3 years ago

The 32 students in Ms.Byrd's art class made a project with construction paper. Eleven students used red construction paper, 8 st

Mice21 [21]

Answer: The correct answer is C. 13/32

Step-by-step explanation: There are 32 students, and 11 + 8 = 19. SO in order to figure out how many students used blue, we need to subtract 19 from 32. that gives us 13. So:

13 out of 32 students, or

13/32

5 0

2 years ago

Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD

Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = $\sqrt{75+25}$ = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that $\frac{1}{2} * BF = \frac{1}{2} * 5 * \sqrt{75}$ and BF= $0.5\sqrt{75}$ . Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is $A= BF * \frac{AB+CD}{2} = 0.5 \sqrt{75} * \frac{5+10}{2} = 18.75 \sqrt{3} cm^{2}$