Solutions
The terminal side of an angle in standard position is a ray that has been rotated from the positive (x) <span>axis.
</span>If the angle measure is positive <span>the rotation is counterclockwise
</span>If the angle measure is negative the <span>rotation is counterclockwise.
</span>
The angle measure is positive, so the rotation is 135° is <span>counterclockwise.
</span>
Rotate the ray 135° counterclockwise. This rotation puts the terminal side in Quadrant <span>II.</span>
Answer:
16 1/4 or 65/4
Step-by-step explanation:
Answer:
sin theta = +(√23)/5
Step-by-step explanation:
Did you know that the cosine is an even function, so that cos (-theta) = cos (+theta)?
Thus we have:
cos(θ)= −√2/5 , sinθ>0
If the cosine of theta is negative, that means that the terminal side of theta is in either Quadrant II or III. Since the sine of theta is positive, we can deduce that theta is in Quadrant II.
Given cos(θ)= −√2/5, we square both sides, obtaining (cos theta)^2 = 2/25. Using the formula (sin theta)^2 + (cos theta)^2 = 1, we arrive at:
(sin theta)^2 = 1 - 2/25, or 23/25.
Then sin theta = +(√23)/5.
Answer:
code a is anywhere from 1 to infinite
Step-by-step explanation:
Answer:
<em><u>110</u></em>
Step-by-step explanation:
<em><u>20</u></em><em><u>/</u></em><em><u>100</u></em><em><u>×</u></em><em><u>550</u></em><em><u>=</u></em><em><u>110</u></em>
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