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Scrat [10]
3 years ago
12

I'm old and have forgotten all math lol...How do I write 113 4 different ways...First Grade math

Mathematics
1 answer:
Zina [86]3 years ago
7 0

its 113 4 man thanks for free points

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Quadrilaterals-what are all other names for quadrilateral parallelograms
iren2701 [21]
Square
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They all have a four sides
5 0
3 years ago
X = y 2 - 1
pochemuha
Your answer would be option B. 2y² - y - 6 = 0. This is because if you were to substitute x = y² - 1 into the equation 2x - y = 4, you would get 2(y² - 1) - y = 4, which expands into 2y² - 2 - y = 4, and then simplifies to 2y² - y - 6 = 0.
I hope this helps!
7 0
3 years ago
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What is the least number by which 384 should be multiplied to make it a perfect square?
mel-nik [20]

Answer:

hcf is the answer questions and I will

3 0
3 years ago
The answer is red show step by step of the pro tem to get the answer
miskamm [114]

In order to rationalize the denominator of each expression, we need to multiply the expression by the same radical in the denominator, this way we can remove the radical from the denominator.

9)

\frac{5\sqrt{4}}{\sqrt{3}}(\cdot\sqrt{3})=\frac{5\sqrt{4}\sqrt{3}}{(\sqrt{3})^2}=\frac{5\cdot2\cdot\sqrt{3}}{3}=\frac{10\sqrt{3}}{3}

10)

-\frac{5}{3\sqrt{2}}(\cdot\sqrt{2})=-\frac{5\sqrt{2}}{3(\sqrt{2})^2}=-\frac{5\sqrt{2}}{3\cdot2}=-\frac{5\sqrt{2}}{6}

11)

\frac{2\sqrt{3}}{4\sqrt{5}}(\cdot\sqrt{5})=\frac{2\sqrt{3}\sqrt{5}}{4(\sqrt{5})^2}=\frac{2\sqrt{15}}{4\cdot5}=\frac{\sqrt{15}}{2\cdot5}=\frac{\sqrt{15}}{10}

12)

\frac{\sqrt{5}}{\sqrt{2}}(\cdot\sqrt{2})=\frac{\sqrt{5}\sqrt{2}}{(\sqrt{2})^2}=\frac{\sqrt{10}}{2}

3 0
1 year ago
What is 8.1% of 18.43
IrinaK [193]

9514 1404 393

Answer:

  1.49283

Step-by-step explanation:

8.1% as a decimal is 0.081

The product of that and 18.43 is ...

  0.081 × 18.43 = 1.49283

__

If this is a monetary value, it would round to 1.49.

5 0
3 years ago
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