Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that 
74% of student are taking an English class
This means that 
70% of students are taking both
This means that 
Find the probability that a randomly selected student is taking a math class or an English class.
This is
, which is given by:

So

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Answer:
3m + 5
Step-by-step explanation:
Just add like terms. ( 5m - 2m) (10 - 5)
Answer:x=2.114
Step-by-step explanation:
Given


Let 





Taking
both sides



Lets say there are x blue marbles.
Purple marbles = 5 + 3x
Blue marbles = x
Total = 65
5 + 3x + x = 65
5 + 4x = 65
4x = 65 - 5 = 60
x = 60/4 = 15
Blue marbles = 15
65 - 15 = 50
There are 50 purple marbles.