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Anton [14]
4 years ago
11

Suppose that demand in period 1 was 7 units and the demand in period 2 was 9 units. Assume that the forecast for period 1 was fo

r 5 units. If the firm uses exponential smoothing with an alpha value of .20, what should be the forecast for period 3? (Round answers to two decimal places.)
Mathematics
1 answer:
Zepler [3.9K]4 years ago
8 0

Answer:

Step-by-step explanation:

Forecast for period 1 is 5

Demand For Period 1 is 7

Demand for Period  2 is 9  

Forecast  can be given by

F_{t+1}=F_t+\alpha (D_t-F_t)

where

F_{t+1}=Future Forecast

F_t=Present\ Period\ Forecast

D_t=Present\ Period\ Demand

\alpha =smoothing\ constant  

F_{t+1}=5+0.2(7-5)

F_{t+1}=5.4

Forecast for Period 3

F_{t+2}=F_{t+1}+\alpha (D_{t+1}-F_{t+1})

F_{t+2}=5.4+0.2\cdot (9-5.4)

F_{t+2}=6.12  

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In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70
Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that P(A) = 0.77

74% of student are taking an English class

This means that P(B) = 0.74

70% of students are taking both

This means that P(A \cap B) = 0.7

Find the probability that a randomly selected student is taking a math class or an English class.

This is P(A \cup B), which is given by:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

1 - P(A \cup B) = 1 - 0.81 = 0.19

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0
3 years ago
5m + 10 - 2m - 5<br> Simplify
crimeas [40]

Answer:

3m + 5

Step-by-step explanation:

Just add like terms. ( 5m - 2m) (10 - 5)

7 0
3 years ago
Read 2 more answers
Starting at the same point, Tom and Juanita go biking in opposite directions. If Tom rides at a speed of 18 mph, and Juanita rid
adell [148]
72 miles
one hour= 18+18
second hour= 18+18
3 0
3 years ago
Solve the following exponential equations.<br> 10^(x+1) − 10^(x−1) = 1287
Rudiy27

Answer:x=2.114

Step-by-step explanation:

Given

10^{x+1}-10^{x-1}=1287

10\times 10^x-\frac{10^x}{10}=1287

Let 10^x=y

10y-\frac{y}{10}=1287

\frac{100y-y}{10}=1287

99y=1287\times 10

y=\frac{12870}{99}=130

10^x=130

Taking \logboth sides

x\log (10)=\log (130)

x=\frac{\log (130)}{1}

x=2.114

7 0
3 years ago
A bag contains purple marbles and blue marbles, 65 in total. The number of purple marbles is 5 more than 3 times the number of b
Marianna [84]
Lets say there are x blue marbles.

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4x = 65 - 5 = 60
x = 60/4 = 15

Blue marbles = 15

65 - 15 = 50

There are 50 purple marbles.
8 0
3 years ago
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