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4 years ago

Find the sum.

Mathematics

2 answers:

BabaBlast [244]4 years ago

8 0

Answer:

Step-by-step explanation:

-3x⁴ – 9x³ - 4x² + 0x + 4

-3x⁴ - 8x³ - 4x² - x - 2

Maslowich4 years ago

4 0

Answer:

C is the answer my friend

Step-by-step explanation:

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A can of pineapple has a height of 13 cm and a diameter of 10 cm, What is the surface of the label that is on it in cm^2

labwork [276]

Answer:

408.46cm^2

Step-by-step explanation:

Given data

Height= 13cm

Diameter= 10cm

Radius= D/2= 10/2= 5cm

The area of the curved surface will be = 2πr × h = 2πrh

substitute

Area of the curved surface = 2πrh= 2*3.142*5*13

Area of the curved surface = 2πrh= 408.46cm^2

Hence the area of the curve surface is 408.46cm^2

3 0

3 years ago

5/6-1/16 please help me

nalin [4]

0.77083333333 I hope that helps

6 0

3 years ago

Read 2 more answers

The lengths of two sides of the right triangle ABC are given. Find the length of the missing side.

pogonyaev

Hey there! :D

Plug it into the Pythagorean theorem.

a^2+b^2= c^2

a^2+16^2= 65^2

Square the numbers.

a^2 + 256= 4225

Subtract 256 on both sides.

a^2= 3969

Find the square root of 3969.

a= 63

I hope this helps!
~kaikers

3 0

3 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

3 years ago

PLEASE HELP MEEEE ILL MARK BRAINLIEST

Gnesinka [82]

DON'T WORRY!

(3x + 2)(3x + 2)(3x - 2)

Notice that (3x + 2) and (3x + 2) are the same, so combining both together becomes this form: $(3x + 2)^{2}$

And looking at the choices now, notice that the first option is correct if I turn/replace the (3x + 2)(3x + 2)(3x - 2) into $(3x + 2)^{2}$ (3x - 2)

ANSWER: Choose the first option $(3x + 2)^{2}$ (3x - 2)

3 0

3 years ago