Help me find the n . Answer with photo please .

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

8 0

Answer:dfngjgkfmdjgkf

Step-by-step explanation:

You might be interested in

Joseph served 18 customers in 42 minutes. Approximately how many customers would he serve in 2 hours if he continued at this rat

zhenek [66]

Okay so if he serves 18 customers in 42 minutes divide 18 by 42 and you get the amount of customers he serves per min which is 0.42857413 then multiply that by 120 since 2 hours add up to 120 minutes and you get 51.43

8 0

3 years ago

BEST ANSWER GETS BRAINLIEST!! HELP PLEASE

skad [1K]

Area of the sign ( trapezoid ) :
A = ( a + b ) / 2 · h
where: a = 8, b = 5, h = 5
A = ( 8 + 6 ) / 2 · 5 =
= 14/2 · 5 = 7 · 5 = 35 ft²
Answer:
B ) 35 square feet

7 0

3 years ago

Read 2 more answers

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$