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3 years ago

HELP NOW PLZ AND I WILL LOVE YOU FOREVER

Mathematics

1 answer:

mr_godi [17]3 years ago

8 0

Answer:

12/4+13=16 2+22/4=7.5

Step-by-step explanation:

you answer is the last option im 100 percent sure.

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Please help with number 3!! I can’t figure it out.

FrozenT [24]

Answer:

Gabe worked 65, Abe worked 62 and Babe worked 69.

Step-by-step explanation:

Let Gabe = x

Therefore, Abe worked: x-3 and Babe worked x+4

So,

x+(x-3)+(x+4)=196

3*x+1=196

3*x=195

x=65

Then,

x-3= 62

x+4=69

8 0

2 years ago

Compare the functions.

marshall27 [118]

Function h has the largest y-intercept which is 44

Step-by-step explanation:

Any linear function is represented in the form

$f(x) = mx+b$

Here b is the y-intercept of the linear function i.e. the constant term in the function.

We will compare all the functions with the general form we get

y-intercept of f(x) = 1

y-intercept of g(x) = 8

y-intercept of h(x) = 44

y-intercept of j(x) = 0

Hence,

Function h has the largest y-intercept which is 44

Keywords: intercepts, linear functions

Learn more about intercepts at:

#LearnwithBrainly

5 0

2 years ago

We randomize a sample for all the following reasons EXCEPT:

kirza4 [7]

Answer:

Step-by-step explanation:

6 0

2 years ago

Seven more then 3 rimes a number is 49

NikAS [45]

7 more than 3 times a number 
more than is code for + 
times is multiply 
so 7+3n=31 

solve: 
3n=24 
n= 8

6 0

3 years ago

Read 2 more answers

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

1 year ago