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marshall27 [118]
2 years ago
12

A savings account pays 1/2% simple interest per year. Anna opens an account and deposits $600. After that, she does not withdraw

or deposit any more money? How much will be in the account after on year?
Mathematics
1 answer:
amid [387]2 years ago
4 0

Answer:

  $603

Step-by-step explanation:

The amount of interest is given by ...

  I = Prt

where P is the principal ($600), r is the interest rate (0.005), and t is the time in years (1). Then the amount of interest after 1 year is ...

  I = $600·.005·1 = $3

That is added to the account balance, so the total is ...

  $600 + $3 = $603 . . . . end-of-year balance

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Plz Help if possible
MrRa [10]

Answer:

2x + y = 2.

Step-by-step explanation:

First  find the slope of the required line by writing the line 2x + y = -5 in slope intercept form:

2x + y = -5

y = -2x - 5

- so the slope is -2.

Therefore the required equation is

y = -2x + 2    (where  2 is the y-intercept).

Converting to standard form:

y = -2x + 2

2x + y = 2.

3 0
3 years ago
Points B, D, and F are midpoints of the sides of ΔACE. EC = 38 and DF = 16. Find AC. The diagram is not to scale.
Lunna [17]

Answer: The measure of AC is 32.

Explanation:

It is given that the Points B, D, and F are midpoints of the sides of ΔACE. EC = 38 and DF = 16.

The midpoint theorem states that the if a line segments connecting two midpoints then the line is parallel to the third side and it's length is half of the third side.

Since F and D are midpoints of AE and EC respectively.

So by midpoint theorem length of AC is twice of DF.

AC=2\times DF

AC=2\times 16

AC=32

Therefore, the length of AC is 32.

7 0
2 years ago
Find the value of the variable What is x?
yaroslaw [1]

Answer:

x = 7

Step-by-step explanation:

I think there may be other ways to do this ... but this is one I  guess....

one angle= 90 ( given)

the other = 45 (given)

the third = 90 + 45 + a = 180  

(all angles of triangles is 180 [angle sum property])

                a = 180 - 135

                   = 45

The base angles are equal so that means it is a isoscles triangle. In isoscles triangle, two sides are equal ,  so

if one side is 7

the x is 7 too

(as it cant be the hypothenus)

I think this is right

5 0
2 years ago
A student needed to find the measure of angle b. She incorrectly said m
devlian [24]
Measure of angle b= 27°

It’s a right angle, so 90-63=27!!!!!
5 0
2 years ago
Read 2 more answers
What is the largest possible integral value in the domain of the real-valued function
kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

  • Antiderivatives
  • Integral Property: \int {cf(x)} \, dx = c\int {f(x)} \, dx
  • Integration Method: U-Substitution
  • [Integration] Reverse Power Rule: \int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = \frac{1}{\sqrt{800-2x} }

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

u = 800-2x\\du = -2dx

<u>Step 3: Integrate</u>

  1. Define:                                                                                                            \int {f(x)} \, dx
  2. Substitute:                                                                                         \int {\frac{1}{\sqrt{800-2x} } } \, dx
  3. [Integral] Int Property:                                                                                     -\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx
  4. [Integral] U-Sub:                                                                                           -\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du
  5. [Integral] Rewrite:                                                                                          -\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du
  6. [Integral - Evaluate] Reverse Power Rule:                                                 -\frac{1}{2}(2\sqrt{u}) + C
  7. Simplify:                                                                                                         -\sqrt{u} + C
  8. Back-Substitute:                                                                                            -\sqrt{800-2x} + C
  9. Factor:                                                                                                           -\sqrt{-2(x - 400)} + C

<u>Step 4: Identify Domain</u>

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0
3 years ago
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