3/11 is the simplified version of this fraction
I've attached the complete question.
Answer:
Only participant 1 is not cheating while the rest are cheating.
Because only participant 1 has a z-score that falls within the 95% confidence interval.
Step-by-step explanation:
We are given;
Mean; μ = 3.3
Standard deviation; s = 1
Participant 1: X = 4
Participant 2: X = 6
Participant 3: X = 7
Participant 4: X = 0
Z - score for participant 1:
z = (x - μ)/s
z = (4 - 3.3)/1
z = 0.7
Z-score for participant 2;
z = (6 - 3.3)/1
z = 2.7
Z-score for participant 3;
z = (7 - 3.3)/1
z = 3.7
Z-score for participant 4;
z = (0 - 3.3)/1
z = -3.3
Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96
Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.
Thus, only participant 1 is not cheating while the rest are cheating.
Answer:
yes because every time x changes y changes the same amount
Step-by-step explanation:
Answer:
add 1 and subtract 1
Step-by-step explanation:
so if u add and subtract 1. take 5. 5+1 and -1 is 4 and 6
Hope this helps :D
Log 10 100 =2
Basically, we have to know how to solve for x in this equation:
10^x = 100
For log3 = 9 we have to solve for x in this equation:
3^x = 9
Therefore, x = 2
