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Diano4ka-milaya [45]
3 years ago
12

1)

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
8 0
◆ Straight Lines ◆

Heya !

1) \: line \: is \: passing \: through \:points \: (5,7) \: and \: (6,8) \\ \\ slope \: of \: line \: = \frac{(y2 - y1)}{(x2 - x1)} \\ \\ slope \: = \: \frac{(8 - 7)}{(6 - 5)} = \: 1 \\ \\ equation \: of \: line \: = \: (y - y1) \: = m (x - x1) \\ \\ equation \: of \: line \: =( y - 7) = 1(x - 5) \\ \\ equation \: of \: line \: - \\ x - y + 2 = 0 \: ans. \\ \\ \\ 2) \: line \: is \: passing \: through \: ( - 3,6) \: and \: ( 3, - 6) \\ \\ slope \: of \: line \: = \frac{(y2 - y1)}{(x2 - x1)} \\ \\ slope \: of \: line \: = \frac{( - 6 - 6)}{(3 - ( - 3))} = - 2 \\ \\ equation \: of \: line = (y - y1) = m(x - x1) \\ \\ equation \: of \: line \: = (y - 6) = - 2(x + 3) \\ \\ equation \: of \: line \: - \\ 2x + y = 0 \: ans. \\ \\ hope \: it \: helps \: you :)

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zaharov [31]

Answer:

Step-by-step explanation:

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6 0
3 years ago
A 14 ​-pound mixture of coffee that contains both decaffeinated and regular coffee costs ​$37. The decaffeinated coffee costs ​$
nikdorinn [45]

Answer:

The number of pounds of:

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Regular coffee = y = 9 pounds

Step-by-step explanation:

A 14 ​-pound mixture of coffee that contains both decaffeinated and regular coffee costs ​$37. The decaffeinated coffee costs ​$2 per​ pound, and the regular coffee costs ​$3 per pound.

Let the number of pounds of:

Decaffeinated coffee = x

Regular coffee = y

Hence, our system of equations =

x + y = 14..... Equation

x = 14 - y

2x + 3y = 37....... Equation 2

We substitute 14 - y for x in Equation 2

= 2(14 - y) + 3y = 37

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Solving for x

x = 14 - y

x = 14 - 9

x = 5 pounds

Therefore,

The number of pounds of:

Decaffeinated coffee = x = 5 pounds

Regular coffee = y = 9 pounds

7 0
3 years ago
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