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sukhopar [10]
3 years ago
13

Yasmine is having a birthday party with snacks and activities for her guests. At one table, five people are sharing three-quarte

rs of a pizza. What equal-sized portion of the whole pizza will each of the five people receive?
a. Use a model (e.g., picture, number line, or manipulative materials) to represent the quotient.
b. Write a number sentence to represent the situation. Explain your reasoning.
c. If three-quarters of the pizza provided 12 pieces to the table, how many pieces were in the pizza when it was full? Support your answer with models.

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0

Answer:

a) photo

b)

\frac{1}{5}  \times  \frac{3}{4}  =  \frac{3}{20}

each person will get 1/5 of the amount of pizza in the table.

the pizza in the table is 3/4 of the whole pizza.

then each person will get 1/5 of 3/4 of the whole pizza.

c)

if 3/4 of the pizza equals 12 slices, then 4/4 of the pizza (the whole pizza) will have 12 . 1 : 3/4 =16 slices

12 \times  \frac{4}{4}  \div \frac{3}{4} = 12 \times  1 \times  \frac{4}{3}  =  \frac{48}{3}  = 16

(Photo)

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ladessa [460]

Answer:

(-2, 4, -2)

x=-2, y=4, z=-2.

Step-by-step explanation:

So we have the three equations:

4x-y-2z=-8\\-2x+4z=-4\\x+2y=6

And we want to find the value of each variable.

To solve this system, first look at it and consider what you should try to do.

So we can see that the second and third equations both have an x.

Therefore, we can isolate the variables for the second and third equation and then substitute them into the first equation to make the first equation all xs.

Therefore, let's first isolate the variable in the second and third equation.

Second Equation:

-2x+4z=-4

First, divide everything by -2 to simplify things:

x-2z=2

Subtract x from both sides. The xs on the left cancel:

(x-2z)-x=2-x\\-2z=2-x

Now, divide everything by -2 to isolate the z:

z=-\frac{2-x}{2}

So we've isolated the z variable. Now, do the same to the y variable in the third equation:

x+2y=6

Subtract x from both sides:

2y=6-x

Divide both sides by 2:

y=\frac{6-x}{2}

Now that we've isolated the y and z variables, plug them back into the first equation. Therefore:

4x-y-2z=-8\\4x-(\frac{6-x}{2})-2(-\frac{2-x}{2})=-8

Distribute the third term. The -2s cancel out:

4x-(\frac{6-x}{2})+(2-x)=-8

Since there is still a fraction, multiply everything by 2 to remove it:

2(4x-(\frac{6-x}{2})+(2-x))=2(-8)

Distribute:

8x-(6-x)+2(2-x)=-16\\8x-6+x+4-2x=-16

Combine like terms:

8x+x-2x-6+4=-16\\7x-2=-16

Add 2 to both sides:

7x=-14

Divide both sides by 7:

(7x)/7=(-14)/7\\x=-2

Therefore, x is -2.

Now, plug this back into the second and third simplified equations to get the other values.

Second equation:

z=-\frac{2-x}{2}\\ z=-\frac{2-(-2)}{2}\\z=-\frac{4}{2}\\z=-2

Third equation:

y=\frac{6-x}{2}\\y=\frac{6-(-2)}{2}\\y=\frac{8}{2}\\y=4

Therefore, the solution is (-2, 4, -2)

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Step-by-step explanation:

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