2.544392* 10^3
In scientific notation
<u>Given</u>:
Given that K is the center of the circle.
The measure of ∠NLQ is 44°
The measure of arc MP is 60°
We need to determine the measure of arc NQ
<u>Measure of arc NQ:</u>
Let us apply the property that, "if the measure of an angle formed by two secants drawn from a point outside the circle is equal to half the difference of the measures of the intercepted arcs".
Thus, we have;
Substituting the values, we have;
Adding both sides by 60, we get;
Thus, the measure of arc NQ is 148°
Answer:
l
Step-by-step explanation:
l
Answer:
x = -4/3 x =1/2
Step-by-step explanation:
6x^2 +5x - 4 = 0
6 has factors of 3 and 2 and 6 and 1
4 has factors of -4 and 1 and -2 and 2, and -1 and 4
We want +5 in the middle
3* -1 + 4*2 = 5
( 3x+4) ( 2x -1) =0
Using the zero product property
3x+4 =0 2x-1 =0
3x = -4 2x =1
x = -4/3 x =1/2